[英]How to create a new merged javascript object based on available keys and user's input
如果我有可用的密鑰,例如:
[
"cars[].model",
"cars[].make",
"cars[].year",
"toys.color",
"toys.type[].brand",
"toys.type[].price",
"id",
"books[].publisher[].authors[]"
]
其中cars[].model 表示cars 是一個對象數組,其中model 作為鍵之一。
如果輸入是:
{
"cars": [
{
"make": "Audi"
},
{
"model": "A8",
"year": "2007"
}
],
"id": "xyz",
"extra": "test",
"toys": {
"color": "Black",
"type": [
{
"price": "$100"
}
]
}
}
如何根據這些可用鍵和輸入對象創建對象?
目標輸出:
{
"cars": [
{
"model": "",
"make": "Audi",
"year": ""
},
{
"model": "A8",
"make": "",
"year": "2007"
}
],
"toys": {
"color": "Black",
"type": [
{
"brand": "",
"price": "$100"
}
]
},
"id": "xyz",
"books": [
{
"publisher": [
{
"authors": []
}
]
}
],
"extra": "test"
}
如果可用的鍵不存在,則值為空。
我曾嘗試展平/取消展平嵌套對象,但徒勞無功。
任何幫助,將不勝感激。
這是遞歸的工作。 我定義了一個函數addKeysRec
,它將添加input
數組中缺少的元素:
function addKeysRec(input, keyArray, recursiveCalls=0) {
if (recursiveCalls == keyArray.length) return
const k = keyArray[recursiveCalls]
if (k == "[]") {
if (!input.length && recursiveCalls + 1 < keyArray.length) input.push({})
input.forEach(s => addKeysRec(s, keyArray, recursiveCalls + 1))
} else {
if (!input.hasOwnProperty(k)) {
if (keyArray[recursiveCalls + 1] == null) input[k] = ''
else if (keyArray[recursiveCalls + 1] == '[]') input[k] = []
else input[k] = {}
}
addKeysRec(input[k], keyArray, recursiveCalls + 1)
}
}
作用中的函數:
const keys = [
"cars[].model",
"cars[].make",
"cars[].year",
"toys.color",
"toys.type[].brand",
"toys.type[].price",
"id",
"books[].publisher[].authors[]"
]
const input = {
"cars": [
{
"make": "Audi"
},
{
"model": "A8",
"year": "2007"
}
],
"id": "xyz",
"extra": "test",
"toys": {
"color": "Black",
"type": [
{
"price": "$100"
}
]
}
}
function addKeysRec(input, keyArray, recursiveCalls=0) {
if (recursiveCalls == keyArray.length) return
const k = keyArray[recursiveCalls]
if (k == "[]") {
if (!input.length && recursiveCalls + 1 < keyArray.length) input.push({})
input.forEach(s => addKeysRec(s, keyArray, recursiveCalls + 1))
} else {
if (!input.hasOwnProperty(k)) {
if (keyArray[recursiveCalls + 1] == null) input[k] = ''
else if (keyArray[recursiveCalls + 1] == '[]') input[k] = []
else input[k] = {}
}
addKeysRec(input[k], keyArray, recursiveCalls + 1)
}
}
keys.forEach(key => {
keyArray = key.replace(/\[\]/g, '.[]').split(".")
addKeysRec(input, keyArray)
})
console.log(input)
輸出:
{
"cars": [
{
"model": "",
"make": "Audi",
"year": ""
},
{
"model": "A8",
"make": "",
"year": "2007"
}
],
"toys": {
"color": "Black",
"type": [
{
"brand": "",
"price": "$100"
}
]
},
"id": "xyz",
"books": [
{
"publisher": [
{
"authors": []
}
]
}
],
"extra": "test"
}
線路:
key = key.replace(/\[\]/g, '.[]').split(".")
是將每個鍵轉換為數組,例如,從格式"cars[].model"
到["cars", "[]", "model"]
。
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