使用方法 includes() 檢查字符串中是否出現數組中表示的字符返回 true - 從字符串中刪除字符

Question

我正在構建一個 URL slug 生成器，我需要的行為是，如果輸入的是：

Ok Now Let's Do This & See

輸出需要是

ok-now-lets-do-this-see

刪除& , ' , and ,字符

 let newStr; function slugifyString(str) { let forbiddenChars = ["&", "'", ","]; newStr = str.toLowerCase().replace(/\\s/g, '-'); if (newStr.includes(forbiddenChars) > -1) { console.log('a forbidden character is present') } } document.getElementById('slug-a-string-form').addEventListener('submit', function(e) { e.preventDefault(); let inputStr = document.getElementById('string-to-slug').value slugifyString(inputStr); document.getElementById('slugged-string').innerHTML = newStr; });

 #slugged-string { color: green; font-size: 15px; padding-top: 20px; }

 <form id="slug-a-string-form" action="POST"> <input type="text" id="string-to-slug" placeholder="enter the string to want to slug here..."> <input type="submit" value="Submit"> </form> <div id="slugged-string"></div>

這適用於如下字符串：

Testing This Out With Something TitleLike

它很笨拙，但它表示存在被禁止的字符，但實際上它不存在。 為什么會這樣？

如何檢查字符串是否包含 JavaScript 中子字符串數組中的文本？

我稍微調整了一下並嘗試了這個：

 let newStr; function slugifyString(str) { let forbiddenChars = ["&", "'", ","]; newStr = str.toLowerCase().replace(/\\s/g, '-'); let forbiddenCharsLength = forbiddenChars.length; while(forbiddenCharsLength--) { if (newStr.indexOf(forbiddenChars[forbiddenCharsLength])!=-1) { if(forbiddenChars[forbiddenCharsLength] == "&") { newStr = newStr.replace("-&", '') } else { newStr = newStr.replace(forbiddenChars[forbiddenCharsLength], '') } } } } document.getElementById('slug-a-string-form').addEventListener('submit', function(e) { e.preventDefault(); let inputStr = document.getElementById('string-to-slug').value slugifyString(inputStr); document.getElementById('slugged-string').innerHTML = newStr; });

 #slugged-string { color: green; font-size: 15px; padding-top: 20px; }

 <form id="slug-a-string-form" action="POST"> <input type="text" id="string-to-slug" placeholder="enter the string to want to slug here..."> <input type="submit" value="Submit"> </form> <div id="slugged-string"></div>

基於控制台的輸出：

it is: '
it is: &

它似乎在循環訪問禁止字符的每次迭代。

輸入：

Ok Now Let's Do This & See

我們現在得到正確的輸出：

ok-now-lets-do-this-see

但是我們說：

Ok Now Let's Do This & That & See, what happens if we have more than one, comma

我們得到：

ok-now-lets-do-this-that-&-see-what-happens-if-we-have-more-than-one,-comma

我不確定為什么它沒有刪除每個被禁止的字符，因為我們正在循環它。

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replace

如果 pattern 是字符串，則只會替換第一個出現的位置。

我知道它只替換它一次，但是

while(forbiddenCharsLength--) {
    if (newStr.indexOf(forbiddenChars[forbiddenCharsLength])!=-1) {
      if(forbiddenChars[forbiddenCharsLength] == "&") {
        newStr = newStr.replace("-&", '')
      } else {
        newStr = newStr.replace(forbiddenChars[forbiddenCharsLength], '')
      }
    }

我們正在做一個 while 循環並在每個匹配項上執行一個 if 命令，所以不應該為每個實例運行替換......？

我在這里缺少什么？

Answer 1

嘗試使用 replaceAll 函數而不是替換。

Answer 2

您可能想嘗試以下解決方案：

 const s = "Ok Now Let's Do This & That & See, what happens if we have more than one, comma"; const slug = s.replaceAll(/[',&]/g, '').replaceAll(/\\s+/g, '-').toLowerCase(); console.log(slug);

Answer 3

您可以將字符串拆分為每個字母的數組，然后刪除（映射到“”）每個禁止的字母，然后將空格替換為 -

  let forbiddenChars = ["&", "'", ","];
  let newStr = str
    .toLowerCase()
    .split("")
    .map(ch => forbiddenChars.includes(ch) ? '' : ch)
    .join("")
    .replace(/\s/g, '-');

 function slugifyString(str) { let forbiddenChars = ["&", "'", ","]; let newStr = str .toLowerCase() .split("") .map(ch => forbiddenChars.includes(ch) ? '' : ch) .join("") .replace(/\\s/g, '-'); if (newStr.includes(forbiddenChars) > -1) { console.log('a forbidden character is present') } return newStr; } document.getElementById('slug-a-string-form').addEventListener('submit', function(e) { e.preventDefault(); let inputStr = document.getElementById('string-to-slug').value let outputStr = slugifyString(inputStr); document.getElementById('slugged-string').innerHTML = outputStr; });

 #slugged-string { color: green; font-size: 15px; padding-top: 20px; }

 <form id="slug-a-string-form" action="POST"> <input type="text" id="string-to-slug" placeholder="enter the string to want to slug here..."> <input type="submit" value="Submit"> </form> <div id="slugged-string"></div>

Answer 4

您可以使用不需要的字符/子字符串迭代數組，並用破折號替換最后的空格。

 function slugify(s) { return ['&', ',', '\\''] .reduce((s, c) => s.replaceAll(c, ' '), s) .replace(/\\s+/g, '-'); } console.log(slugify('Ok Now Let\\'s Do This & That & See, what happens if we have more than one, comma'));