python：元組搜索列表

Question

在這里需要一些幫助

num = [(1,4,5,30,33,41,52),(2,10,11,29,30,36,47),(3,15,25,37,38,58,59)]

如果找到最后 6 位數字，則返回第一位數字。

例如如果找到 10,11,29,30,36,47 返回 2

Answer 1

您可以將next與條件生成器表達式一起使用：

num = [(1,4,5,30,33,41,52),(2,10,11,29,30,36,47),(3,15,25,37,38,58,59)]
search = 11

next(first for first, *rest in num if search in rest)
# 2

Answer 2

您可以使用next類似用戶的方法：

num = [(1,4,5,30,33,41,52),(2,10,11,29,30,36,47),(3,15,25,37,38,58,59)]
to_find = [10,11,29,30,36,47]

print(next(n for n, *nums in num if nums == to_find))

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2