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[英]How to update entity with OneToMany relationship in Spring Boot
[英]update @OneToMany relationship (Spring Boot, Spring Data)
我有一個OneToMany關系(兩個表雙向)。 當我保存醫生的專業時,它確實有效,但是當我刪除任何專業並更新醫生時,它不起作用。
醫生
@Entity
@Table(name = "doctors")
public class Doctor implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer doctorId;
@Column(length = 20)
private String doctorName;
@Column(length = 9)
private String doctorPhoneNo;
@Column(length = 30)
private String doctorEmailAddress;
private String doctorProfileImage;
@Enumerated(EnumType.STRING)
private Status status;
@Column(length = 6)
private String doctorCmp;
@OneToMany(mappedBy = "doctor", cascade = CascadeType.ALL)
// @JsonIgnore
private Set<DoctorSpecialties> doctorSpecialties;
public Doctor() {
this.doctorSpecialties = new HashSet<>();
}
public Doctor(Integer id){
this();
this.doctorId = id;
}
// getters y setters
}
專業
@Entity
@Table(name = "specialties")
public class Specialty implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer specialtyId;
private String specialtyName;
@OneToMany(mappedBy = "specialty")
@JsonIgnore
private Set<DoctorSpecialties> doctorSpecialties;
public Specialty() {
}
public Specialty(Integer id) {
this.specialtyId = id;
}
// getters and setters
}
醫生專長
@Entity
@Table(name = "doctor_specialties")
public class DoctorSpecialties implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "doctor_id")
private Doctor doctor;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "specialty_id")
private Specialty specialty;
@OneToMany
@JoinColumn(name = "doctor_specialties_id")
private Set<Appointment> appointments;
@OneToMany
@JoinColumn(name = "doctor_specialties_id")
private Set<DoctorSchedule> schedules;
public DoctorSpecialties(){
}
public DoctorSpecialties(Specialty specialty, Doctor doctor){
this.specialty = specialty;
this.doctor = doctor;
}
getters / setters
}
控制器
@PostMapping(value = "/saveSpecialties/{id}")
public String saveDoctorSpecialties(@RequestParam(required = false) String[] specialtiesId,
@PathVariable Integer id, RedirectAttributes message) {
if (id != null && id > 0) {
Doctor doctor = doctorService.findOne(id);
if (doctor != null) {
// It does not work
doctor.getDoctorSpecialties().forEach(ds -> doctorSpecialtiesService.delete(ds.getId()));
doctor.getDoctorSpecialties().clear();
if (specialtiesId != null) {
for (String specialtyId : specialtiesId) {
DoctorSpecialties ds = new DoctorSpecialties();
ds.setSpecialty(new Specialty(Integer.parseInt(specialtyId)));
ds.setDoctor(doctor);
doctor.getDoctorSpecialties()
.add(ds);
}
}
doctorService.update(doctor);
message.addFlashAttribute("success", "Specialties successfully saved.");
return "redirect:/doctors/profile/{id}/specialties";
}
}
// specialtiesId = new String[]{};
message.addFlashAttribute("error", "Doctor doesn't exists");
return "redirect:/doctors/list";
}
安慰:
2021-10-30 21:19:13.330 DEBUG 44504 --- [nio-8080-exec-7] org.hibernate.SQL :選擇doctor0_.doctor_id 作為doctor_i1_3_0_,doctor0_.doctor_cmp 作為doctor_c2_3_0_doctor_c2_3_0_addressdoctor_c2_3_0_doctor_c2_3_0_0 .doctor_name 作為doctor_n4_3_0_,doctor0_.doctor_phone_no 作為doctor_p5_3_0_,doctor0_.doctor_profile_image 作為doctor_p6_3_0_,doctor0_.status 作為status7_3_0_ 從醫生doctor0_ 那里doctor0_.doctor_id=? 2021-10-30 21:19:13.339 DEBUG 44504 --- [nio-8080-exec-7] org.hibernate.SQL:選擇doctorspec0_.doctor_id作為doctor_i2_2_0_,doctorspec0_.id作為id1_2_1.id_doctor_id_doctor_id_doctor_id_doctor_id_doctor_id .doctor_id 作為doctor_i2_2_1_,doctorspec0_.specialty_id 作為specialt3_2_1_ 來自doctor_specialties doctorspec0_ where doctorspec0_.doctor_id=? 2021-10-30 21:19:13.401 DEBUG 44504 --- [nio-8080-exec-8] org.hibernate.SQL:選擇doctor0_.doctor_id作為doctor_i1_3_0_,doctor0_.doctor_cmp作為doctor_c2_3_0_addressdoctor_c2_3_0_doctor_c2_3_0_doctor_c2_3_0_0 .doctor_name 作為doctor_n4_3_0_,doctor0_.doctor_phone_no 作為doctor_p5_3_0_,doctor0_.doctor_profile_image 作為doctor_p6_3_0_,doctor0_.status 作為status7_3_0_ 從醫生doctor0_ 那里doctor0_.doctor_id=? 2021-10-30 21:19:13.404 DEBUG 44504 --- [nio-8080-exec-8] org.hibernate.SQL :選擇 specialt0_.specialty_id 作為 specialt1_7_0_,doctorspec1_.id 作為 id1_2_1_doctor,doctor_i_doctor1_doctor_1_doctor_i_23. .specialty_name如specialt2_7_0_,doctorspec1_.doctor_id如doctor_i2_2_1_,doctorspec1_.specialty_id如specialt3_2_1_,doctorspec1_.specialty_id如specialt3_2_0__,doctorspec1_.id如id1_2_0__,doctor2_.doctor_cmp如doctor_c2_3_2_,doctor2_.doctor_email_address如doctor_e3_3_2_,doctor2_.doctor_name如doctor_n4_3_2_,doctor2_.doctor_phone_no作為doctor_p5_3_2_,doctor2_.doctor_profile_image asdoctor_p6_3_2_,doctor2_.status as status7_3_2_ from specialties special0_內連接doctor_specialties doctorspec1_ on special0_.specialty_id=doctorspec1_.specialty_id 內連接doctor2_ ondoctorspec1_.ctor_do=doctor_id 2021-10-30 21:19:13.565 DEBUG 44504 --- [nio-8080-exec-4] org.hibernate.SQL :選擇 specialt0_.specialty_id 作為 specialt1_7_0_,doctorspec1_.id 作為 id1_2_1_,doctor_i_doctor,doctor_i_23_doctor .specialty_name如specialt2_7_0_,doctorspec1_.doctor_id如doctor_i2_2_1_,doctorspec1_.specialty_id如specialt3_2_1_,doctorspec1_.specialty_id如specialt3_2_0__,doctorspec1_.id如id1_2_0__,doctor2_.doctor_cmp如doctor_c2_3_2_,doctor2_.doctor_email_address如doctor_e3_3_2_,doctor2_.doctor_name如doctor_n4_3_2_,doctor2_.doctor_phone_no作為doctor_p5_3_2_,doctor2_.doctor_profile_image asdoctor_p6_3_2_,doctor2_.status as status7_3_2_ from specialties special0_內連接doctor_specialties doctorspec1_ on special0_.specialty_id=doctorspec1_.specialty_id 內連接doctor2_ ondoctorspec1_.ctor_do=doctor_id
沒有刪除語句...
------------------------ 編輯 1 ------------------------
Doctor find = doctorRepository.findById(1).get();
DoctorSpecialties ds1 = new DoctorSpecialties();
ds1.setSpecialty(specialtyRepository.findById(1).get());
ds1.setDoctor(find);
DoctorSpecialties ds2 = new DoctorSpecialties();
ds2.setSpecialty(specialtyRepository.findById(2).get());
ds2.setDoctor(find);
find.getDoctorSpecialties().add(ds1);
find.getDoctorSpecialties().add(ds2);
doctorRepository.save(find);
我做了一些測試,我不能完全理解。 我做了,它只在我實際添加兩個對象時保存一次。
insert into doctor_specialties (id, doctor_id, specialty_id) values (null, ?, ?)
------------------------ 編輯 2 ------------------------
DoctorSpecialties (修改構造函數)
@Entity
@Table(name = "doctor_specialties")
public class DoctorSpecialties implements Serializable {
public DoctorSpecialties(Integer specialtyId, Doctor doctor) {
this.specialty = new Specialty(specialtyId);
this.doctor = doctor;
}
}
控制器
@PostMapping(value = "/saveSpecialties/{id}")
public String saveDoctorSpecialties(@RequestParam(required = false) String[] specialtiesId,
@PathVariable Integer id, RedirectAttributes message) {
if (id != null && id > 0) {
doctorService.saveDelete(id);
Doctor doctor = doctorService.findOne(id);
if (specialtiesId != null && specialtiesId.length > 0) {
for(String idSpecialty : specialtiesId){
doctorSpecialtiesService.save(new DoctorSpecialties(Integer.parseInt(idSpecialty), doctor));
}
}
message.addFlashAttribute("success", "Specialties successfully saved.");
return "redirect:/doctors/profile/{id}/specialties";
}
message.addFlashAttribute("error", "Doctor doesn't exists");
return "redirect:/doctors/list";
}
服務
@Override
@Transactional
public void saveDelete(Integer doctorId) {
Doctor doctor = this.doctorRepository
.findById(doctorId).get();
doctor.getDoctorSpecialties().clear();
}
安慰:
選擇doctor0_.doctor_id如doctor_i1_3_0_,從醫生doctor0_ doctor0_.doctor_cmp如doctor_c2_3_0_,doctor0_.doctor_email_address如doctor_e3_3_0_,doctor0_.doctor_name如doctor_n4_3_0_,doctor0_.doctor_phone_no如doctor_p5_3_0_,doctor0_.doctor_profile_image如doctor_p6_3_0_,doctor0_.status如status7_3_0_其中doctor0_.doctor_id = ? 選擇doctorspec0_.doctor_id作為doctor_i2_2_0_,doctorspec0_.id作為id1_2_0_,doctorspec0_.id作為id1_2_1_,doctorspec0_.doctor_id作為doctor_i2_2_1_,doctorspec0_.specialty_id作為specialt3_2_1_來自doctor_specialties_doctorspec_doctor_specialties_doctor_spec
更新預約 set doctor_specialties_id=null where doctor_specialties_id=?
更新doctor_schedules 設置doctor_specialties_id=null 哪里doctor_specialties_id=?
從doctor_specialties 中刪除id=?
對於事務中的一對多關系,一旦您獲得父級 ( Doctor
) 並遍歷其子級 ( DoctorSpecialties
) [換句話說,一旦您將整個父級及其子級加載到 Persistent 狀態],您將不會能夠通過其repository
直接刪除您的DoctorSpecialties
。
您可以嘗試類似下面的示例來查看它:
@Transactional
public void removeLine(Long doctorId, Long specId) {
Doctor doctor = this.doctorRepository // (1)
.findById(doctorId)
.orElseThrow(IllegalArgumentException::new);
this.doctorSpecialtiesRepository.deleteById(specId); // (2)
}
在(1)中,我們將doctor
加載到持久狀態。 所以在這里,如果fetch = FetchType.EAGER
,這意味着它將把doctor
和它所有的doctor
doctorSpecialties
到持久狀態,這個原因 (2) 不會給你任何影響。
否則,如果fetch = FetchType.LAZY
,它只加載doctor
到持久狀態,並且在(2)它將被成功地刪除。
你的情況很相似,雖然fetch = FetchType.LAZY
,但你使用forEach
循環了孩子,並將doctorSpecialties
加載到持久狀態。 這就是您無法刪除它們的原因。
建議:在您的父實體中使用orphanRemoval = true
@OneToMany(mappedBy = "doctor", cascade = CascadeType.ALL, orphanRemoval = true)
private Set<DoctorSpecialties> dss;
只需在您的方法中清除其子項(在@Transactional 方法中)
doctor.getDoctorSpecialties().clear();
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