[英]Find the index of element in an array against another array
假設我有兩個對象數組
arrayOne = [{revision: { id: 1 }}, {revision: { id: 2 }}, {revision: { id: 3 }}, {revision: { id: 4 }}]
arrayTwo = [{someOtherProp: { id: 2 }}, {someOtherProp: { id: 4 }}]
如何檢查在IDS arrayTwo
針對IDS arrayOne
並返回類似ID出現的結果指標像現在這樣[1, 3]
基於arrayOne
我們可以在索引1和索引3有發生在IDS看到arrayTwo
)
這應該工作
arrayOne = [{revision: { id: 1 }}, {revision: { id: 2 }}, {revision: { id: 3 }}, {revision: { id: 4 }},{revision: { id: 5 }}];
arrayTwo = [{someOtherProp: { id: 2 }}, {someOtherProp: { id: 4 }}];
console.log(arrayOne.filter(o1 => arrayTwo.some(o2 => o1.revision.id === o2.someOtherProp.id)).map(x => arrayOne.findIndex(y => y.revision.id === x.revision.id))); // [1, 3]
這應該適用於您的情況:
one = [{revision: { id: 1 }}, {revision: { id: 2 }}, {revision: { id: 3 }}, {revision: { id: 4 }}]
two = [{someOtherProp: { id: 2 }}, {someOtherProp: { id: 4 }}]
for(let i in two) {
for(let j in one) {
if(two[i]['someOtherProp']['id']==one[j]['revision']['id']){
console.log(i,j)
}
}
}
你可以使用這個工具:
arrayTwo.map(v=>{return v['someOtherProp']['id']}).map(v=>{
return arrayOne.map(v=>{return v['revision']['id']}).indexOf(v)
})
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