[英]How to deliver a matrix to a function that prints it?
我被要求取一個 4x5 的矩陣並掃描每一行(這就是 for 方法的原因),然后打印前半部分,然后打印后半部分。
我相信問題不在函數內部,因為它們在數組上工作正常
當它嘗試打印時,我得到隨機數和零 -
0.000000
-107374176.000000
-107374176.000000
-107374176.000000
-107374176.000000
0.000000
-107374176.000000
-107374176.000000
-107374176.000000
-107374176.000000
0.000000
164582.031250
0.000000
0.000000
0.000000
0.000000
0.000000
0.000000
846674930930036512480361854271488.000000
0.000000
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void scanFloats(float** arr, int size); // scans the floats
void printFloats(float* arr, int size); // prints the floats
int main()
{
float matrix[4][5];
for (int i = 0; i < 4; i++)
{
scanFloats(matrix[i], 5);
}
printFloats(matrix, 10);
printFloats(matrix + 10, 10);
}
void scanFloats(float** arr, int size)
{
*arr = malloc(sizeof(float) * size);
for (int i = 0; i < size; i++) {
printf("Enter number\n");
scanf("%f", (*arr) + i);
}
}
void printFloats(float* arr, int size)
{
for (int i = 0; i < size; i++)
{
printf("%f\n", *(arr + i));
}
}
使用與您的數組相同的類型:
void printFloats(size_t rows, size_t cols, float arr[rows][cols]);
int main(void)
{
float matrix[4][5] = {
{1,2,3,4,5},
{10,20,30,40,50},
{100,200,300,400,500},
{1000,2000,3000,4000,5000},
};
printFloats( 4, 5, matrix);
}
void printFloats(sizet rows, size_t cols, float arr[rows][cols])
{
for (size_t r = 0; r < rows; r++)
{
for (size_t c = 0; c < cols; c++)
{
printf("%8.2f", arr[r][c]);
}
printf("\n");
}
}
與掃描功能相同:
void scanFloats(size_t rows, size_t cols, float arr[rows][cols])
{
for (size_t r = 0; r < rows; r++)
{
for (size_t c = 0; c < cols; c++)
{
scanf("%f", &arr[r][c]);
}
}
}
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