使用php多字段搜索MySQL數據庫

Question

我快到了，我的代碼沒有顯示任何結果。
這是用戶按郵政編碼和物業類型進行搜索的基本形式。
他們應該能夠通過僅輸入郵政編碼或同時輸入兩者來進行搜索。
我在本地主機 php7 中工作
這里的html

<form action="phpSearch.php" method="post">
    <input type="text" placeholder="Search" name="postcode" id="postcode">
    <select name="type" id="type">
        <option value="Terraced">Terraced</option>
        <option value="Detached">Detached</option>
    </select>
    <button type="submit" name="submit">Search</button>
</form>

這里的php

<?php
$postcode = $_POST['postcode'];
$type = $_POST['type'];


$servername = "localhost";
$username = "root";
$password = "";
$db = "priceverification";

$conn = new mysqli($servername, $username, $password, $db);

if ($conn->connect_error){
    die("Connection failed: ". $conn->connect_error);
}

$sql = "SELECT * from house WHERE $type like '%$postcode%'";

$result = $conn->query($sql);
  if($result){
if ($result->num_rows > 0){
while($row = $result->fetch_assoc()){
    echo $row["postcode"]."  ".$row["type"]."  ".$row["town"]."<br>";
}
} else {
    echo "0 records";
}
 }else {
                echo "<br> Database error.";
            }
$conn->close();
?>

數據庫在這里

Answer 1

由於多種原因， $type like '%$postcode%'是無效代碼。 您需要根據來自表單的值構建搜索條件。

以下是代碼的正確外觀：

<?php

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli("localhost", "root", "", "priceverification");
$conn->set_charset('utf8mb4'); // always set the charset

$postcode = $_POST['postcode'] ?? '';
$type = $_POST['type'] ?? '';

$wheres = [];
$values = [];
if ($postcode) {
    $wheres[] = 'postcode LIKE ?';
    $values[] = '%'.$postcode.'%';
}
if ($type) {
    $wheres[] = 'type = ?';
    $values[] = $type;
}
$where = implode(' AND ', $wheres);
if ($where) {
    $sql = 'SELECT * from house WHERE '.$where;
} else {
    $sql = 'SELECT * from house';
}

$stmt = $conn->prepare($sql);
$stmt->bind_param(str_repeat('s', count($values)), ...$values);
$stmt->execute();
$result = $stmt->get_result();

if ($result->num_rows > 0) {
    foreach ($result as $row) {
        echo $row["postcode"] . "  " . $row["type"] . "  " . $row["town"] . "<br>";
    }
} else {
    echo "0 records";
}