[英]Get all possible combinations from a list as tuples
上下文:我正在學習 python 並且我正在嘗試在不使用 itertools 的情況下進行排列。 我有一個包含 3 個足球隊的列表,我想在他們之間進行所有可能的比賽(因此,對於team
列表中的 3 支team
,我們將有 6 場可能的比賽,4 支球隊將是 12 場比賽,等等)。
我試圖做這樣的事情:
team = ["FCP", "SCP", "SLB"]
def allMatches(lst):
teams = []
for index in range(0,len(lst)-1):
for element in lst:
if teams[index][0] != teams[index][1]: #I was trying to make it so that tuples that have the same team are excluded - ('FCP','FCP') would not be appended for example, but I'm calling teams when it has 0 items appended so this won't do nothing
teams.append(tuple((element,team[index-1])))
return teams
allMatches(team)
所需的輸出將是這樣的:
[('FCP','SCP'), ('FCP','SLB'), ('SCP','FCP'), ...]
先感謝您
這將修復您的代碼:
team = ["FCP", "SCP", "SLB"]
def allMatches(lst):
teams = []
for element_list1 in lst:
for element_list2 in lst:
if element_list1 != element_list2:
teams.append(tuple((element_list1, element_list2)))
return teams
allMatches(team)
使用列表理解會更好:
team = ["FCP", "SCP", "SLB"]
def allMatches(lst):
return [(el1, el2) for el1 in lst for el2 in lst if el1!=el2]
allMatches(team)
你可以試試這個:
team = ["FCP", "SCP", "SLB"]
teams = []
for index in range(len(team)) :
for index_2 in range(len(team)) :
if index != index_2 :
teams.append(tuple((team[index], team[index_2])))
print(teams)
#[('FCP', 'SCP'),('FCP', 'SLB'),('SCP', 'FCP'),('SCP', 'SLB'),('SLB', 'FCP'),('SLB', 'SCP')]
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