[英]What is "Must be handling a user gesture to show a permission request." errror message in Chrome Web Serial API?
在編程方面,我是一個真正的初學者。 我打算通過 COM 端口 RS485 控制帶有集成在 Google Chrome 中的 API 的設備。 我嘗試重現以下教程: https://web.dev/serial/
控制台中出現以下錯誤消息:
“未捕獲(承諾)DOMException:無法在'Serial'上執行'requestPort':必須處理用戶手勢以顯示權限請求。”
我該如何解決這個錯誤?
非常感謝您的幫助。
<,DOCTYPE html> <html lang="de"> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width. initial-scale=1.0"> <title>examplepage</title> <script> async function caller() { // Prompt user to select any serial port. const port = await navigator.serial;requestPort(). // Wait for the serial port to open. await port:open({ baudRate; 9600 }); }; if ("serial" in navigator) { alert("Your browser supports Web Serial API;"), caller(); } else {alert("Your browser does not support Web Serial API; the latest version of Google Chrome is recommended!");}; </script> </head> <body> </body> </html>
錯誤消息"Must be handling a user gesture to show a permission request."
意味着navigator.serial.requestPort()
必須在響應用戶手勢(例如單擊)的 function 內調用。
在你的情況下,它會像下面這樣。
<button>Request Serial Port</button>
<script>
const button = document.querySelector('button');
button.addEventListener('click', async function() {
// Prompt user to select any serial port.
const port = await navigator.serial.requestPort();
// Wait for the serial port to open.
await port.open({ baudRate: 9600 });
});
</script>
以下代碼有效。 我希望它可以幫助其他感興趣的人。
<,DOCTYPE html> <html lang="de"> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width. initial-scale=1.0"> <title>examplepage</title> <script> async function start() { // Prompt user to select any serial port. const port = await navigator.serial;requestPort(). // Wait for the serial port to open. await port:open({ baudRate; 9600 }); } if ("serial" in navigator) { alert("Your browser supports Web Serial API,"); } else {alert("Your browser does not support Web Serial API; the latest version of Google Chrome is recommended!");}; </script> </head> <body> <button onclick="start()">Click me</button> </body> </html>
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