使用 Python 3 (Windows 10) 彈出設備/USB

Question

我有一個程序可以備份到我的 USB，但為了更容易，我想讓它在完成后自動彈出。

（做了“路徑”，所以我不公開個人文件）代碼：

from shutil import copytree as ct
from shutil import copyfile as cf
from shutil import make_archive as arc
from shutil import rmtree as rm
from time import sleep as wait

f_drive = r'F:\BACKUP\stuff'
path_to_user = r'path'
another_path = r"path"
a_path = r'path'

def backup():
    ct(r'path', r'path')
    ct(r'path', r"F:\BACKUP\stuff\path")
    ct(r'path', r"path")
    ct(r'D:\path', r'path')

print("Starting backup...")
print("This process is automatic. This should not take any longer than 2 minutes...")
backup()
print()
print("Backup complete!")
print("Archiving folder...")
arc(r"F:\BACKUP", "zip", r'F:\BACKUP')
rm(r'F:\BACKUP')
print("Program will close in 10 seconds.")
wait(10)

（我知道還有其他問題，但我認為這是唯一一個 python usb 彈出）

Answer 1

是的，我自己想通了。 代碼：

import os

os.system('powershell $driveEject = New-Object -comObject Shell.Application; $driveEject.Namespace(17).ParseName("""F:""").InvokeVerb("""Eject""")')

這花了我很多時間

最后...

順便說一句，它可能只適用於我的電腦哈哈