如何按鍵值對嵌入的字典列表進行排序？

Question

對於下面嵌入的字典列表，如何根據 key1 路徑的字符串長度對其進行排序？

jobs = [ {"key1":"path/123", "key2":list1}, \
         {"key1":"path/12",  "key2":list2}, \ 
         {"key1":"path/1",   "key2":list3} ]

預期 output

sorted_jobs = [ {"key1":"path/1",   "key2":list3}  \
                {"key1":"path/12",  "key2":list2}, \ 
                {"key1":"path/123", "key2":list1} ]

Answer 1

使用sorted的key參數：

res = sorted(jobs, key=lambda x: len(x["key1"]))
print(res)

Output

[{'key1': 'path/1', 'key2': []}, {'key1': 'path/12', 'key2': []}, {'key1': 'path/123', 'key2': []}]

作為替代方案，您可以使用普通的 Python function，如下所示：

def key(d):
    return len(d["key1"])


res = sorted(jobs, key=key)
print(res)

設置

jobs = [{"key1": "path/123", "key2": []}, \
        {"key1": "path/12", "key2": []}, \
        {"key1": "path/1", "key2": []}]

Answer 2

只需在sorted中定義key function ：

sorted_jobs = sorted(jobs, key=lambda d: len(d['key1']))