如何使用多個括號執行正則表達式，並且僅從包含特定字符的括號生成字符串
[英]How to do Regular Expressions with multiple brackets and only generate string from brackets that contains specific characters
問題描述
所以，我有這個數據
{"ABC":"Hello"},{"DEF":"World"},{"GHI":"!!!"}
如何使正則表達式生成包含ABC的括號內的字符串，以便返回Hello ？
我還想在包含GHI的括號內生成一個字符串，這樣它就會返回!!!
I will be using this in JavaScript, Python, and REGEXP_EXTRACT function in SQL.
1 個解決方案
在一個字符串中用方括號替換兩個單獨的正則表達式
[英]Replacing two separate regular expressions with brackets within one string
如何提取javascript正則表達式中括號之間的部分：answer_postal_address [address]
[英]how do i extract the part between the brackets in javascript regular expressions: answer_postal_address[address]
如何僅從整個字符串的開頭刪除括號中的字符串？
[英]How do I remove the string in brackets only from the beginning of the entire string?
JavaScript - 僅在特定位置刪除方括號的正則表達式
[英]JavaScript - regular expression to remove square brackets only at specific places
我是否應該在Perl和與ECMAScript兼容的正則表達式中轉義右括號字符
[英]Should I escape closing brackets characters in Perl and ECMAScript-compatible regular expressions flavors
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