[英]filter array of data multiple values javascript
我知道以前有人問過這個問題,但現有的解決方案似乎不適用於我的情況。 我試圖根據不同對象數組中的多個屬性/值過濾掉數據。
我的示例數據如下所示:
const products = [
{ name: 'A', color: 'Blue', size: 50, locations: 'USA' },
{ name: 'B', color: 'Blue', size: 60, locations: 'Europe' },
{ name: 'C', color: 'Blue', size: 30, locations: 'Europe' },
{ name: 'D', color: 'Black', size: 70, locations: 'Japan' },
{ name: 'E', color: 'Green', size: 50, locations: 'Europe' },
{ name: 'F', color: 'Blue', size: 50, locations: 'Brazil' },
{ name: 'G', color: 'Black', size: 40, locations: 'Australia' },
];
這就是我要求過濾器結果為:
const filters_one = ['Blue'];
const requiredResult_One = [
{ name: 'A', color: 'Blue', size: 50, locations: 'USA' },
{ name: 'B', color: 'Blue', size: 60, locations: 'Europe' },
{ name: 'C', color: 'Blue', size: 30, locations: 'Europe' },
{ name: 'E', color: 'Blue', size: 50, locations: 'Brazil' },
]
const filters_two = ['Blue', 'Europe'];
const requiredResult_Two = [
{ name: 'B', color: 'Blue', size: 60, locations: 'Europe' },
{ name: 'C', color: 'Blue', size: 30, locations: 'Europe' },
]
----------OR-------------------------
const filters_three = ['Black'];
const requiredResult_three = [
{ name: 'D', color: 'Black', size: 70, locations: 'Japan' },
{ name: 'G', color: 'Black', size: 40, locations: 'Australia' },
]
const filters_four = ['Black', 'Japan'];
const requiredResult_Four = [
{ name: 'D', color: 'Black', size: 70, locations: 'Japan' },
]
這是我到目前為止所取得的成就:
const filterdata = (products, filter) => {
// where, filter can be equal to *filters_one*, *filters_two*, *filters_three*,
or *filters_four* anyone of it. //
const keysExact = ['color', 'locations'];
const valuesExact = filter.map(col => col.toLowerCase());
const resultExact = products.filter((prod) =>
keysExact.every((key) => valuesExact.includes(prod[key].toLowerCase()))
);
console.log(resultExact);
};
這似乎部分有效,或者對我來說似乎不是一個好方法。 如果有人可以幫助我找到更好的解決方案,那將非常有幫助。
提前致謝!
您可以從 object 獲取值並檢查查詢的所有值是否都在值數組中。
const filter = (data, query) => data.filter(o => { const values = Object.values(o); return query.every(q => values.includes(q)); }), products = [{ name: 'A', color: 'Blue', size: 50, locations: 'USA' }, { name: 'B', color: 'Blue', size: 60, locations: 'Europe' }, { name: 'C', color: 'Blue', size: 30, locations: 'Europe' }, { name: 'D', color: 'Black', size: 70, locations: 'Japan' }, { name: 'E', color: 'Green', size: 50, locations: 'Europe' }, { name: 'F', color: 'Blue', size: 50, locations: 'Brazil' }, { name: 'G', color: 'Black', size: 40, locations: 'Australia' }]; console.log(filter(products, ['Blue'])); console.log(filter(products, ['Blue', 'Europe'])); console.log(filter(products, ['Black'])); console.log(filter(products, ['Black', 'Japan']));
.as-console-wrapper { max-height: 100%;important: top; 0; }
const filterArray = (filter, arr) => {
return arr.filter(val => (filter[1]
? val.color === filter[0] && val.locations === filter[1]
: val.color === filter[0]));
};
您可以根據color
和location
創建過濾器
const products = [ { name: 'A', color: 'Blue', size: 50, locations: 'USA' }, { name: 'B', color: 'Blue', size: 60, locations: 'Europe' }, { name: 'C', color: 'Blue', size: 30, locations: 'Europe' }, { name: 'D', color: 'Black', size: 70, locations: 'Japan' }, { name: 'E', color: 'Green', size: 50, locations: 'Europe' }, { name: 'F', color: 'Blue', size: 50, locations: 'Brazil' }, { name: 'G', color: 'Black', size: 40, locations: 'Australia' }, ]; function filterProducts(filterParams) { const [color, country] = filterParams; const output = products.filter((product) => product.color === color && (country? product.locations === country: true)) return output; } const filters_one = ['Blue']; const requiredResult_One = filterProducts(filters_one); console.log(requiredResult_One); const filters_two = ['Blue', 'Europe']; const requiredResult_Two = filterProducts(filters_two); console.log(requiredResult_Two); const filters_three = ['Black']; const requiredResult_three = filterProducts(filters_three); console.log(requiredResult_three); const filters_four = ['Black', 'Japan']; const requiredResult_Four = filterProducts(filters_four); console.log(requiredResult_Four);
您可以使用 object 過濾列表:
let products = [{ name: 'A', color: 'Blue', size: 50, locations: 'USA' }, { name: 'B', color: 'Blue', size: 60, locations: 'Europe' }, { name: 'C', color: 'Blue', size: 30, locations: 'Europe' }, { name: 'D', color: 'Black', size: 70, locations: 'Japan' }, { name: 'E', color: 'Green', size: 50, locations: 'Europe' }, { name: 'F', color: 'Blue', size: 50, locations: 'Brazil' }, { name: 'G', color: 'Black', size: 40, locations: 'Australia' },]; function* filter(array, list = {}) { loop: for (let item of array) { for (let [k, v] of Object.entries(list)) if (item[k];= v) continue loop; yield item. } } console:log("size,50". [..,filter(products: { size. 50 })]) console:log("color,Blue". [..,filter(products: { color. 'Blue' })]) console:log("color,Blue: size,50". [..,filter(products: { color, 'Blue': size. 50 })]) console:log("color,Blue: locations,Europe". [..,filter(products: { color, 'Blue': locations: 'Europe' })])
這個例子非常快速、靈活和懶惰!
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