Postgres Left Join 和條件太慢

Question

我有兩張桌子

sleeps

睡眠標識符	睡覺時間	喚醒時間
141b40f7-688b-43af-8266-3cc4612b8f98	2021-11-25 22:27:30	2021-11-25 22:16:30
e91bd0f8-688b-43af-8266-dsc4612f8490	2021-11-24 22:27:30	2021-11-24 22:16:30

sleepupdates

睡眠標識符	睡覺時間	喚醒時間
141b40f7-688b-43af-8266-3cc4612b8f98	2021-11-25 22:27:30	2021-11-25 22:16:30

sleepupdates表可能包含一些 SleepIds，如果包含，我需要選擇WakeupTime （來自sleepudates而不是sleeps表）。

我認為左連接應該通過合並來解決這個問題，但看起來它花費了太多時間！

它似乎在根據條件過濾之前掃描左表

select s."SleepId", s."BedTime", s."SleepTime", coalesce(su."WakeupTime", s."WakeupTime") from sleeps s
left join sleepupdates su
on s."SleepId"=su."SleepId"
and s."SleepId"='141b40f7-688b-43af-8266-3cc4612b8f98

我需要上述查詢的幫助。

EXPLAIN ANALYZE

Text Format

explain (analyze,buffers,format text) select s."SleepId", s."BedTime", s."SleepTime", coalesce(su."WakeupTime", s."WakeupTime") from sleeps s
left join sleepupdates su
on s."SleepId"=su."SleepId"
and s."SleepId"='141b40f7-688b-43af-8266-3cc4612b8f98';

                                                           QUERY PLAN                                                           
--------------------------------------------------------------------------------------------------------------------------------
 Hash Right Join  (cost=123483.97..130997.74 rows=850932 width=40) (actual time=444.144..628.801 rows=852809 loops=1)
   Hash Cond: (su."SleepId" = s."SleepId")
   Join Filter: (s."SleepId" = '141b40f7-688b-43af-8266-3cc4612b8f98'::uuid)
   Rows Removed by Join Filter: 21396
   Buffers: shared hit=98037, temp read=4910 written=4848
   ->  Seq Scan on sleepupdates su  (cost=0.00..559.89 rows=21289 width=24) (actual time=0.005..2.806 rows=21396 loops=1)
         Buffers: shared hit=347
   ->  Hash  (cost=106199.32..106199.32 rows=850932 width=40) (actual time=438.068..438.068 rows=852809 loops=1)
         Buckets: 65536  Batches: 32  Memory Usage: 2067kB
         Buffers: shared hit=97690, temp written=4786
         ->  Seq Scan on sleeps s  (cost=0.00..106199.32 rows=850932 width=40) (actual time=0.007..263.471 rows=852809 loops=1)
               Buffers: shared hit=97690
 Planning time: 0.237 ms
 Execution time: 667.356 ms
(14 rows)

Indexes on sleepupdates

CREATE INDEX "sleepupdates_SleepId_idx"
    ON public.sleepupdates USING btree
    ("SleepId" ASC NULLS LAST)
    TABLESPACE pg_default;
-- Index: sleepupdates_SleepId_unique

-- DROP INDEX public."sleepupdates_SleepId_unique";

CREATE UNIQUE INDEX "sleepupdates_SleepId_unique"
    ON public.sleepupdates USING btree
    ("SleepId" ASC NULLS LAST, "Status" COLLATE pg_catalog."default" ASC NULLS LAST)
    TABLESPACE pg_default
    WHERE "Status" = 'PENDING'::text;
-- Index: sleepupdates_UserId_idx

-- DROP INDEX public."sleepupdates_UserId_idx";

CREATE INDEX "sleepupdates_UserId_idx"
    ON public.sleepupdates USING btree
    ("UserId" ASC NULLS LAST)
    TABLESPACE pg_default;

SleepId是sleeps表中的主鍵

Answer 1

您正在返回每一行睡眠。 s."SleepId"='141b40f7-688b-43af-8266-3cc4612b8f98條件需要在 WHERE 子句中，而不是在 ON 中。