如何將 Array1 中的元素與 javascript 中 Array2 的每個元素進行比較並返回匹配值

Question

Here I have two objects, and I would like to compare each element of Object 1 with each element of Object 2. Note that the elements of object 1 constitute the property_names of object 2. And if the property_names of Object 1 exists in Object 2,從 Object 2 中刪除所有其他 property_names 並保留匹配的那些。

Object 1

[0: {name: 'Id', match: 'id', matched: true}
1: {name: 'Driver', match: 'fullName', matched: true}
2: {name: 'Sex', match: 'gender', matched: true} ]

Object 2

0: [Id: '1256', Driver: 'Jack Burn', Sexe: 'M', Age: '32', Situation: 'ACTIF', …]
1: [Id: '1896', Driver: 'Sacks Maddison', Sexe: 'M', Age: '25', Situation: 'ABANDONS', …]
2: [Id: '1001', Driver: 'Hilary Michael', Sexe: 'F', Age:'21', Situation: 'ACTIF', Téléphone: 
xxxx, ]

預期結果

因此，目標是讓 object 2 僅具有匹配的 object 1 的屬性：

 0: [Id: '1256', Driver: 'Jack Burn', Sexe: 'M']
 1: [Id: '1896', Driver: 'Sacks Maddison', Sexe: 'M']
 2: [Id: '1001', Driver: 'Hilary Michael', Sexe: 'F']

謝謝

Answer 1

每次迭代第一個數組中的元素時，循環遍歷第二個數組，然后檢查匹配項。

var array1 = ["cat", "sum", "fun", "run"],
    array2 = ["bat", "cat", "dog", "sun", "hut", "gut"];

function getMatch(a, b) {
    var matches = [];

    for ( var i = 0; i < a.length; i++ ) {
        for ( var e = 0; e < b.length; e++ ) {
            if ( a[i] === b[e] ) matches.push( a[i] );
        }
    }
    return matches;
}

getMatch(array1, array2); // ["cat"]