[英]Checking if individual variable is empty from an array PHP
如何檢查數組中是否只有 1 個單獨的變量為空? 我需要一個元素來顯示或不顯示,這取決於變量中是否有內容。 問題是,如果我添加多個變量,它會隱藏/顯示所有元素,而不是單獨顯示。 任何幫助表示贊賞。
什么有效:
PHP:
<?php
$texta = CFS()->get( 'sometexta' );
if ($texta !='') {
$display = 'block';
} else {
$display = 'none';
}
?>
HTML:
<div class="element" style="display:<?php echo $display; ?>">
<p><?php echo $texta; ?></p>
</div>
....
我想做什么:
PHP:
<?php
$texta = CFS()->get( 'sometexta' );
$textb = CFS()->get( 'sometextb' );
$textc = CFS()->get( 'sometextc' );
$alltext = array($texta, $textb, $textc);
foreach ( $alltext as $text) {
if ($text !='') {
$display = 'block';
} else {
$display = 'none';
}
}
?>
HTML:
<div class="element" style="display:<?php echo $display; ?>">
<p><?php echo $texta; ?></p>
</div>
<div class="element" style="display:<?php echo $display; ?>">
<p><?php echo $textb; ?></p>
</div>
<div class="element" style="display:<?php echo $display; ?>">
<p><?php echo $textc; ?></p>
</div>
....
像這樣的東西:
PHP
<?php
$texta = CFS()->get( 'sometexta' );
$textb = CFS()->get( 'sometextb' );
$textc = CFS()->get( 'sometextc' );
$alltext = array($texta, $textb, $textc);
$display = [];
foreach($alltext as $text){
if ($text !='') {
$display[] = 'block';
} else {
$display[] = 'none';
}
}
?>
HTML
<div class="element" style="display:<?php echo $display[0]; ?>">
<p><?php echo $texta; ?></p>
</div>
<div class="element" style="display:<?php echo $display[1]; ?>">
<p><?php echo $textb; ?></p>
</div>
<div class="element" style="display:<?php echo $display[2]; ?>">
<p><?php echo $textc; ?></p>
</div>
我個人會嘗試這樣的事情:
<div class="element" style="display:<?php ($texta!="") ? echo "block" : echo "none"; ?>">
<p><?php echo $texta; ?></p>
</div>
<div class="element" style="display:<?php ($textb!="") ? echo "block" : echo "none"; ?>">
<p><?php echo $textb; ?></p>
</div>
<div class="element" style="display:<?php ($textc!="") ? echo "block" : echo "none"; ?>">
<p><?php echo $textc; ?></p>
</div>
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