[英]Deleting node from binary tree
抽象類的二叉樹。 我有三種刪除方法,第一種是用戶菜單,其他是遞歸的。 刪除一個節點后,我遇到了減少節點計數的問題。 請幫忙,我應該在哪里寫“r->count--”?
Node* Del(Node *t, Node *t0) {
if (t->left != nullptr) {
t->left = Del(t->left, t0);
return t;
}
t0->o = t->o;
Node *x = t->right;
delete t;
return x;
}
Node* deleteNodes(Node *r, Node *elem, bool &deleted) {
bool del;
if (r == nullptr) {
deleted = false;
return r;
}
if (equal(elem->o, r->o) < 0) {
r->left = deleteNodes(r->left, elem, del);
deleted = del;
return r;
}
else if (equal(elem->o, r->o) > 0) {
r->right = deleteNodes(r->right, elem, del);
deleted = del;
return r;
}
deleted = true;
if (r->left == nullptr && r->right == nullptr) {
delete r;
return nullptr;
}
if (r->left == nullptr) {
Node *x = r->right;
delete r;
return x;
}
if (r->right == nullptr) {
Node *x = r->left;
delete r;
return x;
}
r->right = Del(r->right, r);
return r;
}
您應該將它放在找到要刪除的節點的代碼中。 這也是您將deleted
設置為true
地方:
所以:
deleted = true;
r->count--;
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.