[英]Function output wrong when using printf
printf("\n%d",NN+NE+ND+SD+SE+SS+E+D);
This is my functions when I call checkmoves in the main function they give me a value of 4 that it is correct but when I add the printf above to check some values to trying solve another problem the function checkmoves give me back 13 instead of 4.
請注意,我調用 main like printf("\n%d", checkmoves(board,'o'));
int count_flips_dir(char board[8][8],int line, char col,int delta_line,int delta_col,char color){
int i;
if(board[line+delta_line][col+delta_col]=='.'){
return 0;
}
if (delta_line+line<=7 && delta_line+line>=0){
if (delta_col+col<=7 && delta_col+col>=0){
for(i=0;board[line+delta_line][col+delta_col]!=color;i++){
line=delta_line+line;
col=delta_col+col;
if(board[line+delta_line][col+delta_col]=='.'){
return 0;
}
}
}
}
return i;
}
int flanked(char board[8][8],int line,char col,char color ){
int NN = count_flips_dir(board,line,col,-1,0,color);
int ND = count_flips_dir(board,line,col,-1,1,color);
int NE = count_flips_dir(board,line,col,-1,-1,color);
int SS = count_flips_dir(board,line,col,1,0,color);
int SD = count_flips_dir(board,line,col,1,1,color);
int SE = count_flips_dir(board,line,col,1,-1,color);
int D = count_flips_dir(board,line,col,0,1,color);
int E = count_flips_dir(board,line,col,0,-1,color);
return NN+NE+ND+SD+SE+SS+E+D;
}
int checkmoves(char board[8][8],char color){
int i;
int count=0;
char j;
for(i=0;i<8;i++){
for(j=0;j<8;j++){
if (board[i][j]=='.'){
if (flanked(board,i,j,color)>0){
count++;
}
}
}
}
return count;
}
在count_flips_dir
,您測試if(board[line+delta_line][col+delta_col]=='.')
在檢查初始移動是否留在棋盤內之前。
然后您測試初始移動是否停留在矩陣內以搜索顏色,而不是后續移動。
此外,如果初始移動超出電路板,function 將返回i
uninitialized。
我不確定 function 在這種情況下應該返回什么,可能是0
。
這是修改后的版本:
int count_flips_dir(char board[8][8], int line, int col,
int delta_line, int delta_col, char color) {
for (int i = 0;; i++) {
line += delta_line;
col += delta_col;
if (line < 0 || line >= 8 || col < 0 || col >= 8)
return 0;
if (board[line][col] == color)
return i;
if (board[line][col] == '.')
return 0;
}
return i;
}
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