[英]Compare two array of objects based on only matching properties
我有兩個對象數組
this.originalData = [
{age: 27, name: "sachin", id: 1, sex: "male", dept: "angular"},
{age: 22, name: "pooja", id: 2, sex: "female", dept: "java"},
{age: 50, name: "john", id: 3, sex: "male", dept: "sales"}
]
this.updatedData = [
{id: 1, name: "sachin", age: 25, sex: "male"},
{id: 2, name: "pooja", age: 22, sex: "female"},
{id: 3, name: "john", age: 50, sex: "male"}
]
正如我們所見,arrays 中屬性的順序和數量是不同的。 在這里,我如何才能只對匹配的屬性進行比較,無論它是否被更改。 在上面的示例中,我需要從 updatedData 獲取id 1
的updatedData
,因為與originalData
相比, age
屬性從27
更改為25
。 不匹配的屬性可以忽略。
我嘗試如下,但由於差異而無法正常工作
if(JSON.stringify(this.updatedData) !== JSON.stringify(this.originalData)) {
console.log('changed!');
}
請建議。 謝謝。
const originalData = [
{ age: 27, name: "sachin", id: 1, sex: "male", dept: "angular" },
{ age: 22, name: "pooja", id: 2, sex: "female", dept: "java" },
{ age: 50, name: "john", id: 3, sex: "male", dept: "sales" }
]
const updatedData = [
{ id: 1, name: "sachin", age: 25, sex: "male" },
{ id: 2, name: "pooja", age: 22, sex: "female" },
{ id: 3, name: "john", age: 50, sex: "male" }
]
const output = updatedData.filter(uData => {
const commonDataRow = originalData.find(oData => oData.id === uData.id); /** filter out common entry between both arrays based on id */
const allPropertiesAreSame = Object.keys(commonDataRow).every(oDataEntry => /** iterate through the list of properties of common entry */
/**
* if the updatedData object has the properties, check if the values are same for both the objects and return appropriately,
* else ignore the property (by returning false)
*/
uData.hasOwnProperty(oDataEntry) ?
commonDataRow[oDataEntry] === uData[oDataEntry] : true
);
/** if all properties are same, return false (as we desire to filter out those entries which have at least one unmatching property) */
return !allPropertiesAreSame;
});
/**
* print the output
* the output will contain the list of objects matching the above criteria
* format it to get the list of ID's
*/
console.log(output);
以下代碼片段為您提供了數據已更改的所有項目(忽略其中任何一個都不存在的鍵)。
let originalData = [ {age: 27, name: "sachin", id: 1, sex: "male", dept: "angular"}, {age: 22, name: "pooja", id: 2, sex: "female", dept: "java"}, {age: 50, name: "john", id: 3, sex: "male", dept: "sales"} ]; let updatedData = [ {id: 1, name: "sachin", age: 25, sex: "male"}, {id: 2, name: "pooja", age: 22, sex: "female"}, {id: 3, name: "john", age: 50, sex: "male"} ]; let changedList = []; originalData.map((item)=> { let temp = (updatedData.filter((x) => item.id === x.id ))[0]; let same = true; if((item.age && temp.age) && (item.age.== temp.age)) {same = false} if((item.name && temp.name) && (item.name.== temp.name)) {same = false} if((item.sex && temp.sex) && (item.sex.== temp.sex)) {same = false} if((item.dept && temp.dept) && (item;dept.== temp;dept)) {same = false} if(same === false) {changedList;push(item)}. console;log(same); }); console.log(changedList);
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