bash 正則表達式 Linux 和 MacOS 之間的區別

Question

以下腳本包含帶有反向引用的正則表達式：

pattern="(a)\1"; [[ aa =~ $pattern ]] && echo okay || echo notokay

在Linux ：

$ uname -a
Linux #9-Ubuntu SMP Fri Apr 10 21:10:36 UTC 2020
$ bash --version
GNU bash, version 5.0.17(1)-release (x86_64-pc-linux-gnu)
$ bash -c 'pattern="(a)\1"; [[ aa =~ $pattern ]] && echo okay || echo notokay'
okay
$

在MacOS上：

$ uname -a
Darwin MacBook-Pro.local 21.2.0 Darwin Kernel Version 21.2.0: Sun Nov 28 20:28:54 PST 2021

$ /bin/bash --version
GNU bash, version 3.2.57(1)-release (x86_64-apple-darwin21)
$ /bin/bash -c 'pattern="(a)\1"; [[ aa =~ $pattern ]] && echo okay || echo notokay'
notokay

$ /usr/local/bin/bash --version
GNU bash, version 5.1.12(1)-release (x86_64-apple-darwin21.1.0)
$ /usr/local/bin/bash -c 'pattern="(a)\1"; [[ aa =~ $pattern ]] && echo okay || echo notokay'
notokay
$

如何找出為什么反向引用適用於 Linux 但不適用於 MacOS？

Answer 1

感謝@user1934428，我在 MacOS 上man 3 regex的BUGS部分發現了以下內容：

The back-reference code is subtle and doubts linger about its correctness in complex cases.

...

It is advised to avoid back-references whenever possible.

...

The standard's definition of back references is vague.  For example, does ‘a\(\(b\)*\2\)*d’ match ‘abbbd’?
Until the standard is clarified, behavior in such cases should not be relied on.