Python3-Turtle：筆顏色不變

Question

我有一個繪制磚牆的 function ，可以選擇在繪制牆之前設置某種筆顏色，但是無論我做什么，磚似乎都被繪制為綠色：

def draw_brick(length, width):

    t.color("green")
    t.begin_fill()
    for i in range(2):
        t.forward(length)
        t.right(90)
        t.forward(width)
        t.right(90)
    t.end_fill()

def draw_row(row_type, bricks):
    if row_type == "A":
        for i in range(bricks):
            draw_brick(50, 30)
            t.penup()
            t.forward(70)
            t.pendown()
    elif row_type == "B":
        draw_brick(12, 30)
        t.penup()
        t.forward(35)
        t.pendown()

        for i in range(bricks - 1):
            draw_brick(50, 30)
            t.penup()
            t.forward(70)
            t.pendown()
            
        t.penup()
        t.pendown()
        draw_brick(12, 30)


def draw_brick_wall(rows, brick, top_row, new_color):
    t.pencolor(new_color)

    if top_row == "A":
        drawing_A = True
    else:
        drawing_A = False
    for i in range(rows):
        next_position = (t.xcor(), t.ycor() - 40)

        if drawing_A:
            draw_row("A", brick)
        else:
            draw_row("B", brick)

        drawing_A = not (drawing_A)
        move_no_trails(next_position[0], next_position[1])


# resets turtle to postion (x, y)
def move_no_trails(x, y):
    t.penup()
    t.goto(x, y)
    t.pendown()

但是，由於某種原因，烏龜的筆顏色沒有改變。 我能做些什么來解決這個問題？

Answer 1

一旦我添加了兼容的draw_brick() function，您的代碼就可以正常工作：

from turtle import Screen, Turtle

def draw_brick(width, height):
    for _ in range(2):
        turtle.forward(width)
        turtle.left(90)
        turtle.forward(height)
        turtle.left(90)

def draw_row(row_type, bricks):
    if row_type == "A":
        for _ in range(bricks):
            draw_brick(50, 30)
            turtle.penup()
            turtle.forward(70)
            turtle.pendown()
    elif row_type == "B":
        draw_brick(12, 30)
        turtle.penup()
        turtle.forward(35)
        turtle.pendown()

        for _ in range(bricks-1):
            draw_brick(50, 30)
            turtle.penup()
            turtle.forward(70)
            turtle.pendown()

        draw_brick(12, 30)

# resets turtle to postion (x, y)
def move_no_trails(x, y):
    turtle.penup()
    turtle.goto(x, y)
    turtle.pendown()

def draw_brick_wall(rows, brick, top_row, new_color):
    turtle.pencolor(new_color)

    drawing_A = top_row == "A"

    for _ in range(rows):
        next_x, next_y = turtle.xcor(), turtle.ycor() - 40

        if drawing_A:
            draw_row("A", brick)
        else:
            draw_row("B", brick)

        drawing_A = not drawing_A
        move_no_trails(next_x, next_y)

screen = Screen()

turtle = Turtle()
turtle.speed('fastest')  # because I have no patience

draw_brick_wall(1, 5, "A", "red")
draw_brick_wall(1, 5, "B", "blue")
draw_brick_wall(1, 5, "A", "orange")
draw_brick_wall(1, 5, "B", "green")

screen.exitonclick()

但是，如果您的draw_brick() function 正在繪制填充磚，那么您需要將 draw_brick_wall() 中對pencolor(new_color)的調用更改為draw_brick_wall() fillcolor(new_color)以將填充顏色或color(new_color)設置為設置筆和填充 colors。

Answer 2

請提供整個代碼，包括您如何調用draw_brick_wall function。 您也可以嘗試使用不同的 IDE。