[英]How to print full char array gdb
如何打印完整的aligned_depth.get_data()。 它應該是一個字符數組: https://gist.github.com/richardrl/224eb53d4bc1cedda36f5bda1d78ca18#file-realsense_multicam-cpp-L39
這些是我嘗試過的一些事情:
(gdb) print *aligned_depth.get_data()@depth_size
Attempt to dereference a generic pointer.
(gdb) print (char*) aligned_depth.get_data()@depth_size
Only values in memory can be extended with '@'.
(gdb) print (char*)aligned_depth.get_data()@depth_size
Only values in memory can be extended with '@'.
這應該有效:
(gdb) p *((char*)aligned_depth.get_data())@depth_size
考慮到這個測試,至少它對我使用 GDB-10.0 有效:
const char p[] = "abcd\0efgh";
const int data_size = sizeof(p);
const void* get_data() { return p; }
int main() { return 0; }
gcc -g -w x.c && gdb -ex start -q ./a.out
Reading symbols from ./a.out...
Temporary breakpoint 1 at 0x113a: file x.c, line 5.
Starting program: /tmp/a.out
Temporary breakpoint 1, main () at x.c:5
5 int main() { return 0; }
(gdb) p *((char*)get_data())@data_size
$1 = "abcd\000efgh"
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