如何將 append 元組從 for 循環到列表

Question

inter = []

for inter in intersections:

    a, b = inter
    for i in range(6):
        for j in range(6):
            lines_edges[int(b) + i, int(a) + j] = [0, 0, 255]
            cv2.circle(lines_edges,(int(a),int(b)), 5, (0, 255, 0), cv2.FILLED)


print(inter)

OUTPUT：

(255.49047141424273, 253.22266800401204)
(261.42908992416034, 227.0)
(312.7111046847889, 227.0)
(361.3178929765886, 296.4939799331104)
(362.0041891809848, 227.5)
(362.5263157894737, 165.73684210526315)
(410.92892156862746, 228.5)
(463.1585111920874, 228.5)

OUTPUT 我想要：

[(255.49047141424273, 253.22266800401204) (261.42908992416034, 227.0) (312.7111046847889, 227.0) (361.3178929765886, 296.4939799331104) (362.0041891809848, 227.5) (362.5263157894737, 165.73684210526315) (410.92892156862746, 228.5) (463.1585111920874, 228.5)]

Answer 1

你只需要：

1. 為結果准備空數組
2. Append 使用append()將元組添加到數組

例如：

result = []
tuples = [(1,2), (3,4)]
for tuple in tuples:
    result.append(tuple)

或者，如果您想從操作中構造元組，例如您希望列表具有包含每個輸入元組的最小值和最大值的元組，您可以執行以下操作：

result = []
tuples = [(3,1,7,2), (3,4,2,1)]
for tuple in tuples:
    inner_tuple = (min(tuple), max(tuple))
    result.append(inner_tuple)

我使用上面的元組列表作為參考，您只需要在 for 循環中使用.append()即可。

您需要更改變量名稱以包含結果，因為當您將變量inter設置為intersections的內部元素時， inter將不再是一個空數組，因此您需要更改它：

# Change inter to result
result = [] 
for inter in intersections:
    # do things here...
    item = .....
    result.append(item)

print(result)

Answer 2

您只需要在循環中的內部列表中使用 append 元組。

inter.append(tuple)

Answer 3

s = []
for inter in intersections:

    a, b = inter

    for i in range(6):
        for j in range(6):

            lines_edges[int(b) + i, int(a) + j] = [0, 0, 255]
            cv2.circle(lines_edges,(int(a),int(b)), 5, (0, 255, 0), cv2.FILLED)


    s.append(inter)
a = [(int(x), int(y)) for x,y in s]
print(a)