如何將整數列表轉換為單值元組

Question

我寫了一個代碼來從數據庫中刪除一些用戶，但它說Incorrect number of bindings supplied. The current statement uses 1, and there are 4 supplied Incorrect number of bindings supplied. The current statement uses 1, and there are 4 supplied 。

def delete_user(self, user_id):
    stmt = "DELETE FROM user WHERE user_id = (?)"
    args = user_id
    try:
        self.conn.executemany(stmt, (args,))
        self.conn.commit()
    except sqlite3.Error as e:
        logging.error(str(e))

我的部分主要代碼：

    deleted_user = []
    deleted_user.append(1384995383)
    deleted_user.append(1667596031)
    deleted_user.append(1332658866)
    deleted_user.append(1295962235)

    print(deleted_user)
    db.delete_user(deleted_user)

我找到了這個答案： sqlite3：提供的綁定數量不正確。 當前語句使用 1，提供了 5 個

我嘗試使用tuple(user_id)將其轉換為元組，但結果不是我除外

來源deleted_user列表：

[1384995383, 1667596031, 1332658866, 1295962235]

在 tuple(user_id) 結果之后：

(1384995383, 1667596031, 1332658866, 1295962235)

我的期望：

[(1384995383,), (1667596031,), (1332658866,), (1295962235,)]

我試圖搜索，但我無法得到我想要的答案:(

Answer 1

嘗試這個：

deleted_user.append((1384995383,))

Answer 2

def delete_user_ids(self, user_ids):
    stmt = "DELETE FROM user WHERE user_id = (?)"
    try:
        self.conn.executemany(stmt, user_ids)
#                                   ^^^^^^^^

user_ids = []
user_ids.append((1384995383,))
user_ids.append((1667596031,))
user_ids.append((1332658866,))
user_ids.append((1295962235,))
delete_user_ids(user_ids)