如何在 mysql 中為每一天（分組）日期

Question

對於我的網站管理面板，我需要顯示兩個日期之間的付款統計信息

我的付款表字段：

+--------------------+--------------+------+-----+-------------------+-----------------------------+
| Field              | Type         | Null | Key | Default           | Extra                       |
+--------------------+--------------+------+-----+-------------------+-----------------------------+
| id                 | int(11)      | NO   | PRI | NULL              | auto_increment              |
| price              | int(11)      | NO   |     | 0                 |                             |
| created            | timestamp    | NO   |     | CURRENT_TIMESTAMP |                             |
+--------------------+--------------+------+-----+-------------------+-----------------------------+

我需要每天通過 php laravel 獲取兩天之間的付款數據到這個結構

// date between 2021-12-01 and 2021-12-03

$data = [
    [
        'date' => '2021-12-01',
        'count' => 5 // number of payments records in 2021-12-01 in payments table
    ],
    [
        'date' => '2021-12-02',
        'count' => 0 // number of payments records in 2021-12-01 in payments table
    ],
    [
        'date' => '2021-12-03',
        'count' => 15 // number of payments records in 2021-12-01 in payments table
    ],
];

您應該知道，也許有一天我沒有任何付款，並且這一天在數據庫中沒有任何記錄。 但我需要以 0 的數量顯示這一天

我不知道怎么做

Answer 1

使用遞歸公用表表達式（在 mysql 8 或 mariadb 10.2+ 中）創建日期表（此處報告日期從 2021-01-01 到 2021-01-31）：

with recursive dates as (
    select date('2021-01-01') date
    union all
    select dates.date + interval 1 day from dates where dates.date < '2021-01-31'
)
select dates.date, count(payments.id)
from dates
left join payments on date(payments.created)=dates.date
group by 1;

Answer 2

您可以使用以下查詢來做到這一點：

select gen_date, count(transactions.id) from

(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) gen_date from
 (select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
 (select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
 (select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
 (select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
 (select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
 left JOIN  transactions
  on date(transactions.created) = date(gen_date)

where gen_date between '2021-12-01' and '2021-12-20'
group by gen_date;

如果你想要 laravel 查詢生成器版本：

    $select = DB::query()->selectRaw("gen_date, count(transactions.id)")->fromSub(function ($query) {
        $query->select("(select adddate('1970-01-01',t4*10000 + t3*1000 + t2*100 + t1*10 + t0) gen_date from
 (select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
 (select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
 (select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
 (select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
 (select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4)");
    }, "v")
        ->leftJoin('transactions', function ($join) {
            $join->on(DB::raw("date(transactions.created)"), "=", DB::raw("date(v.gen_date)"));
        })
        ->whereRaw("gen_date between '2021-12-01' and '2021-12-20'")
        ->groupBy('gen_date')
        ->get();

ps：我從這里獲取的日期范圍子查詢

Answer 3

您可以使用DB::raw() ：

$data = DB::raw('select left(created_at, 10) as date, count(1) as count from payments group by date;');

Answer 4

此代碼可以顯示兩天之間的天數

select * from 
(select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where selected_date between '2021-12-01' and '2021-12-03'

我希望這段代碼可以幫助你

Answer 5

SELECT DATE(created) AS `date`, COUNT(*) AS `count`
FROM source_table
-- WHERE created BETWEEN @period_start AND @period_finish
GROUP BY `date`;