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如何在 python selenium 中為每個測試啟動單獨的瀏覽器

[英]how to launch seperate browser for each test in python selenium

在運行 test_login.py 時,應該啟動 3 個瀏覽器並驗證測試,但只有一個正在啟動,第二個測試失敗,因為第二個測試在第一個測試步驟后繼續。

*********** Conftest.py********** 下面是conftest文件

import pytest
from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager

    @pytest.fixture(scope="class")
    def setup(request):
        driver = webdriver.Chrome(ChromeDriverManager().install())
        driver.get("https://itera-qa.azurewebsites.net/Login")
        driver.maximize_window()
        request.cls.driver = driver
    
        yield
        driver.close()

test_login.py這個測試文件包含 3 個測試來驗證

import pytest
from pages.loginpage import PageLogin


@pytest.mark.usefixtures("setup")
class TestLogin:

    @pytest.fixture(autouse=True)
    def class_setup(self):
        self.tl = PageLogin(self.driver)
        

    @pytest.mark.login
    def test_login1(self):
        self.tl.enter_user_name("sysadm")
        self.tl.enter_password("sysadm")
        self.tl.click_login()

    

    def test_empty_user_pwd(self):
        # self.driver.get(self.url)
        self.tl.enter_user_name("")
        self.tl.enter_password("")
        self.tl.click_login()
        if self.tl.error_text() == 'Login error: Enter your username.':
            assert True
        else:
            assert False

    def test_empty_pwd(self):
        # self.driver.get(self.url)
        self.tl.enter_user_name("sysadm")
        self.tl.enter_password("")
        self.tl.click_login()
        if self.tl.error_text() == 'Login error: Enter your password.':
            assert True
        else:
            assert False

******* PageLogin *********** 這是定義所有 xpath 的登錄頁面

import time

from selenium.webdriver.common.by import By


class PageLogin(SelectCustomer):
    textbox_username_id = "user"
    textbox_password_id = "pass"
    button_login_xpath = "//input[@value='Log In']"
    get_error_text_xpath = "//p[@class='error']"

    def __init__(self, driver):
        self.driver = driver

    def enter_user_name(self, username):
        self.driver.find_element(By.ID, self.textbox_username_id).send_keys(username)

    def enter_password(self, password):
        self.driver.find_element(By.ID, self.textbox_password_id).send_keys(password)

    def click_login(self):
        self.driver.find_element(By.XPATH, self.button_login_xpath).click()

    def error_text(self):
        returned_error_text = self.driver.find_element(By.XPATH, self.get_error_text_xpath).text
        return returned_error_text
        time.sleep(4)

更改 conftest.py 以下代碼中的代碼后問題解決:能夠為每個測試用例啟動單獨的瀏覽器

import pytest
from selenium import webdriver
from webdriver_manager.chrome import ChromeDriverManager
from webdriver_manager.firefox import GeckoDriverManager
from webdriver_manager.microsoft import EdgeChromiumDriverManager
driver = None


@pytest.fixture(autouse=True)
def setup(request, browser, url):
    global driver
    if browser == "chrome":
        driver = webdriver.Chrome(executable_path=ChromeDriverManager().install())
    elif browser == "firefox":
        driver = webdriver.Firefox(executable_path=GeckoDriverManager().install())
    elif browser == "edge":
        driver = webdriver.Edge(EdgeChromiumDriverManager().install())
    driver.get(url)
    driver.maximize_window()
    request.cls.driver = driver
    yield
    driver.close()


#this will get the value of CLI/Hooks
def pytest_addoption(parser):
    parser.addoption("--browser")
    parser.addoption("--url")


#This will return the browser value to setup method
@pytest.fixture(scope="class", autouse=True)
def browser(request):
    return request.config.getoption("--browser")


#This will return the url value to setup method
@pytest.fixture(scope="class", autouse=True)
def url(request):
    return request.config.getoption("--url")

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