在 javascript 中按日期對嵌套的 object 進行排序

Question

如何按日期對數據進行排序並找到連續日期之間的最大值計數？ 示例數據：

const data = {
    'addias':{
        '2022-1-10': ['a', 'b', 'c', 'd', 'e', 'f', 'g'],
        '2022-1-09': ['a', 'b', 'c', 'd', 'e', 'f', 'g'],
        '2021-12-29': ['a'],
        '2021-12-28': ['y', 'u', 'v', 'd', 'f', 'f', 'g'],
        '2021-1-08': ['x', 't', 's', 'd', 'e', 'f', 'g'],
    },
    'nike':{
        '2022-1-20': ['a', 'b', 'c', 'd', 'e', 'f', 'g'],
        '2022-1-15': ['a', 'b', 'c'],
        '2022-1-14': ['a', 'b'],
        '2022-1-10': ['y', 'b', 'x', 'z', 'e', 'f', 'g'],
    }
}

結果就像

const result = {
     'addias':{
        'firstDate': '2022-1-09',
        'secondDate':'2022-1-10',
        'total':14 ,
    },
    'nike':{
        'firstDate': '2022-1-14',
        'secondDate':'2022-1-15',
        'total':5,
    }
}

試圖：

Object.entries(data).forEach((item) => {
   const [ brand, dates ] = item; /** {'2022-1-10': array } */
   let sorted = Object.entries(dates).sort((a,b) => new Date(a[0]) - new Date(b[0]))
   /** find value count for each sorted date */
   
   /** find if the dates are consecutive */

   /** build new object with result property */ 

})

Answer 1

您可以這樣做，盡管您可能想編寫自定義排序 function

 const data = { 'addias':{ '2022-1-10': ['a', 'b', 'c', 'd', 'e', 'f', 'g'], '2022-1-09': ['a', 'b', 'c', 'd', 'e', 'f', 'g'], '2021-12-29': ['a'], '2021-12-28': ['y', 'u', 'v', 'd', 'f', 'f', 'g'], '2021-1-08': ['x', 't', 's', 'd', 'e', 'f', 'g'], }, 'nike':{ '2022-1-20': ['a', 'b', 'c', 'd', 'e', 'f', 'g'], '2022-1-15': ['a', 'b', 'c'], '2022-1-14': ['a', 'b'], '2022-1-10': ['y', 'b', 'x', 'z', 'e', 'f', 'g'], } } const result = {}; Object.keys(data).forEach(sneaker => { const dates = Object.keys(data[sneaker]); dates.sort(); result[sneaker] = { firstDate: dates[0], secondDate: dates[1], total: dates.length }; }); console.log(result);

Answer 2

我認為在計數之前找出日期對會更有效，我認為這應該可以解決問題：

 const data = { 'addias': { '2022-1-10': ['a', 'b', 'c', 'd', 'e', 'f', 'g'], '2022-1-09': ['a', 'b', 'c', 'd', 'e', 'f', 'g'], '2021-12-29': ['a'], '2021-12-28': ['y', 'u', 'v', 'd', 'f', 'f', 'g'], '2021-1-08': ['x', 't', 's', 'd', 'e', 'f', 'g'], }, 'nike': { '2022-1-20': ['a', 'b', 'c', 'd', 'e', 'f', 'g'], '2022-1-15': ['a', 'b', 'c'], '2022-1-14': ['a', 'b'], '2022-1-10': ['y', 'b', 'x', 'z', 'e', 'f', 'g'], } }; function maxValueBetweenConsecutiveDates(input) { const result = {}; for (const brand in input) { const dates = Object.keys(input[brand]).map(e => ({ date: new Date(e), original: e })).sort((a, b) => a.date - b.date); const pairs = []; for (let i = 1; i < dates.length; i++) { if (dates[i].date - dates[i - 1].date === 86400000) { pairs.push([dates[i - 1], dates[i]]); } } const quantities = pairs.map(pair => ({ firstDate: pair[0].original, secondDate: pair[1].original, total: input[brand][pair[0].original].length + input[brand][pair[1].original].length })); const max = Math.max(...quantities.map(e => e.total)); const quantity = quantities.find(e => e.total === max); result[brand] = quantity; } return result; } console.log(maxValueBetweenConsecutiveDates(data));