[英]Deep nested Array of Objects, find and remove Object with specific ID
我正在嘗試通過 ID 查找 Object 並將其刪除。 (當然,如果這個 object 有子任務,那么掛在這棵樹上的所有對象也會被刪除)。 我有一個這樣的結構(例如),它可以變得非常大和深:
[
{
"id": 0,
"lane": 0,
"name": "Task A",
"start": 0,
"end": 10000,
"subTasks": [
{
"id": "0.1",
"lane": 0,
"name": "Subtask",
"start": 0,
"end": 10000,
"class": "danger",
"sublane": 0,
"subTasks": [
{
"id": "0.1.1",
"name": "Subtask",
"start": 0,
"end": 10000,
"subTasks": [
{
"id": "0.1.1.1",
"name": "Subtask",
"start": 0,
"end": 10000,
"subTasks": [
{
"id": "0.1.1.1.1",
"name": "Subtask",
"start": 0,
"end": 10000
},
{
"id": "0.1.1.1.2",
"name": "Subtask",
"start": 0,
"end": 10000
}
]
},
{
"id": "0.1.1.2",
"name": "Subtask",
"start": 0,
"end": 10000
}
]
},
{
"id": "0.1.2",
"name": "Subtask",
"start": 0,
"end": 10000
},
{
"id": "0.1.3",
"name": "Subtask",
"start": 0,
"end": 10000
}
]
},
{
"id": "0.2",
"name": "Subtask",
"start": 0,
"end": 10000
}
],
"class": "danger",
"sublane": 0
},
{
"id": 1,
"lane": 2,
"name": "Task B",
"start": 15000,
"end": 25000,
],
"class": "success",
"sublane": 0
}
]
現在我想刪除 ID = 0.1.1.1.1 例如,但它應該以同樣的方式與其他所有 Object 一起工作,無論它嵌套多深。
使用此 dfs 算法查找和編輯 Im:
edit: function (name, start, end) {
for (let obj of gantt.items()) {
result = dfs(obj, id);
if (result) {
result.name = name;
result.start = start;
result.end = end;
}
}
dfs: function (obj, targetId) {
if (obj.id === targetId) {
return obj;
}
if (obj.subTasks) {
for (let item of obj.subTasks) {
let check = dfs(item, targetId);
if (check) {
return check;
}
}
}
return null;
},
但是如何刪除/刪除特定的 Object?
遞歸過濾器的種類:
const data = [{"id":"0","lane":0,"name":"Task A","start":0,"end":10000,"Subtask":[{"id":"0.1","lane":0,"name":"Subtask","start":0,"end":10000,"class":"danger","sublane":0,"Subtask":[{"id":"0.1.1","name":"Subtask","start":0,"end":10000,"Subtask":[{"id":"0.1.1.1","name":"Subtask","start":0,"end":10000,"Subtask":[{"id":"0.1.1.1.1","name":"Subtask","start":0,"end":10000},{"id":"0.1.1.1.2","name":"Subtask","start":0,"end":10000}]},{"id":"0.1.1.2","name":"Subtask","start":0,"end":10000}]},{"id":"0.1.2","name":"Subtask","start":0,"end":10000},{"id":"0.1.3","name":"Subtask","start":0,"end":10000}]},{"id":"0.2","name":"Subtask","start":0,"end":10000}],"class":"danger","sublane":0},{"id":"1","lane":2,"name":"Task B","start":15000,"end":25000,"class":"success","sublane":0}]; const removeById = (arr, targetId) => arr.reduce((acc, obj) => (obj.id === targetId)? acc: [...acc, {...obj, ...(obj.Subtask && { Subtask: removeById(obj.Subtask, targetId) }) } ], []); console.log(removeById(data, "0.1"));
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