[英]Can someone please tell me how to remove or hide this JavaScript code?
[英]GA4 custom event from server side, can someone tell me how i can do the following code in php?
const measurement_id = `G-XXXXXXXXXX`;
const api_secret = `<secret_value>`;
fetch(`https://www.google-analytics.com/mp/collect?measurement_id=${measurement_id}&`api_secret`=${api_secret}`, {
method: "POST",
body: JSON.stringify({
client_id: 'XXXXXXXXXX.YYYYYYYYYY',
events: [{
name: 'tutorial_begin',
params: {},
}]
})
});
有人可以告訴我如何在 php 中執行上述代碼嗎? 我嘗試了以下方法,但它不起作用,
$data = array(
'client_id' => self::ga_extract_cid_from_cookies(),
'user_id' => 123,
'timestamp_micros' => time(),
'non_perosnalised_ads' => false,
'events' => array(
'name' => 'login'
)
);
$dataString = json_encode($data);
$post_url = 'https://www.google-analytics.com/mp/collect?api_secret=xxxxxxx&measurement_id=xxxxxxxxx';
$ch = curl_init($post_url);
curl_setopt($ch, CURLOPT_POSTFIELDS, $datastring);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));
curl_setopt($ch, CURLOPT_HTTP_VERSION,CURL_HTTP_VERSION_1_1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$result = curl_exec($ch);
當我運行上述內容時,它不會向谷歌分析帳戶發送任何事件。 我不知道錯誤是什么以及如何找到它。 需要幫助。
我相信您的示例中的主要問題,除了 $datastring 變量中的拼寫錯誤外,用戶 id 是作為 int 發送的,而不是作為字符串發送的。 我的例子在這里有效:
$ip = str_replace('.', '', $_SERVER['REMOTE_ADDR']);
$data = array(
'client_id' => $ip,
'user_id' => '123',
'events' => array(
'name' => 'event_serverside'
)
);
$datastring = json_encode($data);
$post_url = 'https://www.google-analytics.com/mp/collect?api_secret=xxxxxxxxxx&measurement_id=xxxxxxxxx';
$ch = curl_init($post_url);
curl_setopt($ch, CURLOPT_POSTFIELDS, $datastring);
curl_setopt($ch, CURLOPT_HTTP_VERSION,CURL_HTTP_VERSION_1_1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, $post_url);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type:application/json'));
curl_setopt($ch, CURLOPT_POST, TRUE);
$result = curl_exec($ch);
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