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無法使用 Laravel Livewire 顯示我的數據庫中的值

[英]Can't display the values from my data base with Laravel Livewire

我正在使用 Livewire 組件,這是我的代碼:

搜索.php:

<?php

namespace App\Http\Livewire;

use Livewire\Component;
use App\Models\Recipe;
use App\Models\Vegetable;
use App\Models\VegetablesRecipe;


class Search extends Component
{
    public $query;
    public $vegetables;

    public function mount()
    {
        $this->resetQuery();
    }

    public function resetQuery()
    {
        $this->vegetables = [];
    }

    public function updateQuery()
    {
        $this->vegetables = Vegetable::where('name', 'like', '%'.$this->query.'%')->get()->toArray();
    }

    public function render()
    {
        return view('livewire.search');
    }
}

search.blade.php:

<div class="searchcomponent">
    <h1>Search</h1>
    <input wire:model="query" type="text" placeholder="Rechercher...">
    
    @if(!empty($query))
        <ul>
            @if(!empty($vegetables))
                <div class="vegetables">

                    @foreach($vegetables as $vegetable)
                        <li><span class="material-icons">lunch_dining</span>{{ $vegetable['name'] }}</li>
                    @endforeach
                
                </div>
            @else
                <li>No result</li>
            @endif
       </ul>
    @endif
</div>

我的菜Model:

<?php

namespace App\Models;

use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;

class Vegetable extends Model
{
    use HasFactory;

    public $timestamps = false;

    protected $fillable = ['name'];

    public function recipes(){
        return $this->belongsToMany(Recipe::class, 'vegetables_recipes', 'vegetable_id', 'recipe_id');
    }

    public function getName($id) {
        return $this->name;
    }
}

我的問題是,每次我在搜索欄中輸入內容時,即使我已經在我的數據庫中播種了一些蔬菜,我的屏幕上也只會出現“無結果”。 為什么當我輸入它時它不顯示例如胡蘿卜?

一旦調用了 function“updateQuery”,您就只需要拉入您的蔬菜。 我建議將它添加到您的渲染中並設置public $query; 到一個空字符串,例如public $query = '';

if ($this->query != null) {
    return view('livewire.search', [
        'vegetables' => Vegetable::where('name', 'like', '%'.$this->query.'%')->get()->toArray()
    ]);
} else {
    return view('livewire.search', [
        'vegetables' => Vegetable::all()->toArray()
    ])
}

這樣,如果查詢為空,它將繼續顯示蔬菜,但是一旦您開始搜索,它將使用 where 子句對其進行過濾。

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