[英]Mysql GROUP_CONCAT return only one value
我嘗試通過GROUP_CONCAT
返回用戶有多少朋友但我只得到Lance
而不是Bob
並且似乎如果我刪除WHERE
條件。 它工作正常,但我想保留它。 因為我想獲取所有連接到member
的行
CREATE TABLE users(
id INT PRIMARY KEY AUTO_INCREMENT,
name VARCHAR(255)
);
INSERT INTO users (name)
VALUES ("Gregor"),
("Liza"),
("Matt"),
("Tim"),
("Lance"),
("Bob");
CREATE TABLE committee(
id INT PRIMARY KEY AUTO_INCREMENT,
user_id INT,
friend_id INT,
member_id INT,
FOREIGN KEY (`user_id`) REFERENCES `users` (`id`),
FOREIGN KEY (`friend_id`) REFERENCES `users` (`id`),
FOREIGN KEY (`member_id`) REFERENCES `users` (`id`)
);
INSERT INTO committee (user_id, friend_id, member_id)
VALUES (3, 5, 1),
(4, 5, 1),
(3, 6, 2),
(4, 6, 2);
這是查詢:
SELECT u.name,
GROUP_CONCAT(f.name) AS friends
FROM committee c
INNER JOIN users u ON (u.id = c.user_id)
INNER JOIN users AS f ON (f.id = c.friend_id)
WHERE (c.member_id = 1)
GROUP BY u.id;
我現在得到的:
name friends
Matt Lance
Tim Lance
我的期望:
name friends
Matt Lance,Bob
Tim Lance,Bob
您需要再次加入committee
才能找到馬特和蒂姆所在的所有其他委員會,這樣您就可以從這些委員會中找到他們的朋友。
SELECT u.name,
GROUP_CONCAT(f.name) AS friends
FROM committee c
INNER JOIN users u ON (u.id = c.user_id)
INNER JOIN committee c2 ON c2.user_id = c.user_id
INNER JOIN users AS f ON (f.id = c2.friend_id)
WHERE (c.member_id = 1)
GROUP BY u.id;
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.