如何計算 python 中字符串中的特殊字符、字母和數字？

Question

string = '98 people are present @ seminar'

def count(string):
    d={}
    for t in string:
        d[t] = string.count(t)
    for k in sorted(d):
        print(k+':' +  str(d[k]))
count(string)

在這里我想為特殊字符和數字添加計數器。 還想獲取字符串的用戶輸入。 我怎么做？

Answer 1

要求用戶輸入字符串使用

variableName = input(PROMPT)

要進行計數，請列出 nums、字母列表和 rest 將是特殊字符 然后循環遍歷列表並使用 if 語句檢查字母是否在帶有.contains()的字符串中

代碼看起來像這樣：

letters = "abcdefghijklmnopqrstuvwxyz"
numbers = "0123456789"
def countString(inputString,characterType):#inputString is the string you want to check characterType is what you want to check for
    count = 0
    inputString = inputString.lower()
    if characterType == "numbers":
        for i in inputString:
            if not(numbers.count(i) == 0):
                count += 1
    elif characterType == "letters":
        for i in inputString:
            if not(letters.count(i) == 0):
                count += 1     
    elif characterType == "specialChars":
        for i in inputString:
            if numbers.count(i) == 0 and letters.count(i) == 0 and not(i == " ") :
                count += 1
    return count

Answer 2

Python 有多種字符串方法來幫助區分字母和數字字符串。 您可以測試這些並根據該測試進行計數。

def count(string):
    d={'letters': 0, 'numbers': 0, 'other': 0}
    for t in string:
        if t.isalpha():
            d['letters'] += 1
        elif t.isdigit():
            d['numbers'] += 1
        else:
            d['other'] += 1 # this will include spaces
    return d

string = input('enter some text: ')
# 98 people are present @ seminar

counts = count(string)
print(counts)
# {'letters': 23, 'numbers': 2, 'other': 6}