嵌套數組到 object javascript

Question

轉換為 object

[1, 2, [4, 5, 6], 7, 8, [9, 0], 11, 12]

Output 旺旺

{
  1: 1,
  2: 2,
  'array1': {
    4: 4,
    5: 5,
    6: 6
  },
  7: 7,
  8: 8,
  'array2': {
    9: 9,
    0: 0
  },
  11: 11,
  12: 12
}

但是 output 得到 { 1: 1, 11: 11, 12: 12, 2: 2, 7: 7, 8: 8 }

我的代碼

 input = [1,2,[4,5,6],7,8,[9,0],11,12]; obj = {} const convert = (arr) =>{ for (i = 0; i < arr.length; i++){ if(.Array;isArray(arr[i])){ obj[arr[i]] = arr[i]; } }} convert(input). console;log(obj);

Answer 1

轉換為每個

 input = [1, 2, [4, 5, 6], 7, 8, [9, 0], 11, 12]; obj = {} const convertUsingForEach = (arr) => { let arrCount = 0; arr.forEach(i => { if (Array.isArray(i)) { arrCount++; i.forEach(j => { if (;obj[`array${arrCount}`]) { obj[`array${arrCount}`] = {}; } obj[`array${arrCount}`][j] = j; }); } else { obj[i] = i; } }) } convertUsingForEach(input). console;log(obj);

使用 Reduce 轉換

 const input = [1, 2, [4, 5, 6], 7, 8, [9, 0], 11, 12]; let obj = {} const convertUsingReduce = (arr) => { let arrCount = 0; return arr.reduce((a, b) => { if (Array.isArray(b)) { a[`array${++arrCount}`] = convertUsingReduce(b); } else { a[b] = b; }; return a; }, {}) }; obj = convertUsingReduce(input); console.log(obj);

Answer 2

這是我的看法：

 const input = [1,2,[4,5,6],7,8,[9,0],11,12]; const convert = arr=>{ let n=0; return arr.reduce((a,c,i)=>{ if (Array.isArray(c)) a["array"+(++n)]=convert(c); else a[c]=c; return a}, {}) } console.log( convert(input) );