如何刪除列表中特定元素的最后兩個字符？

Question

所以我有這些包含元數據的文本文件，我制作了這段代碼來打印它的每一行（第一個元數據文件的）：

path = 'C:\\Users\\basse\\Pictures\\OneM\\metadata\\P5JS metadata\\Metadata'

with open(path + '1.txt') as file:
    lines = []
    for line in file:
        lines.append(line)


print(lines[0], end ="")
print(lines[1], end ="")
print(lines[2], end ="")
print(lines[3], end ="")
print(lines[4], end ="")

現在的問題是第四行和第五行在我的元數據文件中看起來像這樣

1.0
4.0

所以當我打印它時會發生什么：

Blue sky
Blue Ice
Rounded Rectangle
1.0
4.0

如何刪除這些字符的最后兩個字符（So the.0）？

Answer 1

你可以這樣做，

with open(path + '1.txt') as file:
    lines = []
    for line in file:
        lines.append(line. replace(".0", ""))

print(lines[0], end ="")
print(lines[1], end ="")
print(lines[2], end ="")
print(lines[3], end ="")
print(lines[4], end ="")

或者你可以這樣做

with open(path + '1.txt') as file:
    lines = []
    for line in file:
        lines.append(line)

print(lines[0], end ="")
print(lines[1], end ="")
print(lines[2], end ="")
print(lines[3].replace(".0", ""), end ="")
print(lines[4].replace(".0", ""), end ="")

Answer 2

您可以使用正則表達式替換來去除尾隨.0 ：

with open(path + '1.txt') as file:
    lines = []
    for line in file:
        lines.append(re.sub(r'\.\d+$', '', line))

以上實際上將去除任何小數部分。 如果您真的只想定位尾隨.0 ，請使用\.0$ 。