如何使用 Open API 代碼生成器與 WebClient 進行同步調用

Question

RestTemplate 文檔中的 Spring 有注釋：

從 5.0 開始，class org.springframework.web.client.RestTemplate 處於維護模式，只有較小的更改請求和錯誤被接受。 請考慮使用 org.springframework.web.reactive.client.WebClient，它具有更現代的 API 並支持同步、異步和流式處理方案

https://docs.spring.io/spring-framework/docs/current/javadoc-api/org/springframework/web/client/RestTemplate.ZFC35FDC70D5FC69D2639883A822C7A

當我嘗試使用 Open Api 代碼生成器將 RestTemplate 替換為 WebClient 時，我無法進行同步調用。

pom.xml 代碼

<plugin>
    <groupId>org.openapitools</groupId>
    <artifactId>openapi-generator-maven-plugin</artifactId>
    <version>${openapi-tool-version}</version>
    <executions>
        <execution>
            <id>Games</id>
            <goals>
                <goal>generate</goal>
            </goals>
            <configuration>
                <generatorName>java</generatorName>
                <library>webclient</library>
               <inputSpec>${project.basedir}/spec/games.yaml</inputSpec>
                <configOptions>
                    <configPackage>com.tintin.config</configPackage>
                    <apiPackage>com.tintin.api</apiPackage>
                    <modelPackage>com.tintin.model</modelPackage>
                    <invokerPackage>com.tintin.service</invokerPackage>
                    <sourceFolder>src/main/java</sourceFolder>
                    <dateLibrary>java8</dateLibrary>
                </configOptions>
                <generateModelTests>false</generateModelTests>
                <generateApiTests>false</generateApiTests>
            </configuration>
        </execution>
    </executions>
</plugin>

默認情況下，webclient 進行異步調用並將響應包裝在 Mono<> 中。

public <T> Mono<T> invokeAPI(String path, HttpMethod method, Map<String, Object> pathParams, MultiValueMap<String, String> queryParams, Object body, HttpHeaders headerParams, MultiValueMap<String, String> cookieParams, MultiValueMap<String, Object> formParams, List<MediaType> accept, MediaType contentType, String[] authNames, ParameterizedTypeReference<T> returnType) throws RestClientException {
    final WebClient.RequestBodySpec requestBuilder = prepareRequest(path, method, pathParams, queryParams, body, headerParams, cookieParams, formParams, accept, contentType, authNames);
    return requestBuilder.retrieve().bodyToMono(returnType);
}

預期 Output（類似於 resttemplate）

public <T> ResponseEntity<T> invokeAPI(String path, HttpMethod method, Map<String, Object> pathParams, MultiValueMap<String, String> queryParams, Object body, HttpHeaders headerParams, MultiValueMap<String, String> cookieParams, MultiValueMap<String, Object> formParams, List<MediaType> accept, MediaType contentType, String[] authNames, ParameterizedTypeReference<T> returnType) throws RestClientException {
    final WebClient.RequestBodySpec requestBuilder = prepareRequest(path, method, pathParams, queryParams, body, headerParams, cookieParams, formParams, accept, contentType, authNames);
    return requestBuilder.retrieve().bodyToMono(returnType).block();
}

如何使用打開的 api 代碼生成器將 Resttemplate 替換為 Webclient 而不對當前代碼進行任何重大更改

Answer 1

您希望生成 Rest 模板類，但您使用的是<library>webclient</library> ，請更改為<library>resttemplate</library>在此處閱讀整個文檔https://openapi-generator.tech/docs/generators /java/