[英]Invalid JSON path expression. The error is around character position 1
[英]Invalid JSON path expression. The error is around character position
我像這樣將 json 數據插入到 mySql 數據庫中:
{
"socialnetwork": {
"twitter": "tw-u"
},
"information": {
"country": "Cuba",
"state": "Sancti Spiritus"
},
"settings": {
"social-enable": "1"
}
}
現在,我嘗試使用JSON_REPLACED
方法更新social-enable
值,如下所示:
$builder = $this->db->table('users');
$builder->where('id', 2)->set('information', "JSON_REPLACE(information, '$.settings.social-enable', '0')", false) ;
$builder->update();
在行動中我看到這個錯誤:
Invalid JSON path expression. The error is around character position 27.
我該如何解決這個問題?
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.