使用 python 導出 gpx 文件？

Question

我想從https://routing.openstreetmap.de導出（下載）一個 gpx 文件，當你請求方向 url 是這樣的： https://routing.openstreetmap.de/?z=17&center=51.515199%2C-0.092772 &loc=51.514739%2C-0.089800&loc=51.516214%2C-0.096656&hl=en&alt=0&srv=1

使用 python 我想在將新的 loc=lat-lon&loc=lat-lon 插入到 url 后導出 gpx 文件。在檢查站點后，這個跨度 class 可以下載。

請伙計們。 至少一個提示

編輯這部分是在回答后添加的

這是https://routing.openstreetmap.de/?z=15&center=36.614839%2C3.014159&loc=36.600473%2C2.994676&loc=36.623863%2C3.002186&hl=en&alt=0&srv=2的 gpx 文件

並且對於 json 請求，我使用此代碼僅獲得兩分：

import requests
import json

lat_start = 36.5924
lon_start = 2.9898

lat_dist = 36.6429
lon_dist = 2.9929

url = 'https://routing.openstreetmap.de/routed-car/route/v1/driving/'+ str(lat_start)+','+str(lon_start)+';'+str(lat_dist)+','+str(lon_dist)+'?overview=false&alternatives=true&steps=true'
#url = 'https://routing.openstreetmap.de/routed-car/route/v1/driving/-0.0898,51.514739;-0.096656,51.516214?overview=false&alternatives=true&steps=true'
response = requests.get(url)

data = response.json()
print('DATA ___________________________________________________')
print(data)
mrks = []
for elements in data['routes']:
    #print('ROUTES___________________________________________________')
    #print(elements)
    for legs in elements['legs']:
        #print('legs___________________________________________________')
        #print(legs)
        for steps in legs['steps']:
            #print('steps___________________________________________________')
            #print(steps)
            for intersections in steps['intersections']:
                #print('intersections___________________________________________________')
                #print(intersections)
                for location in intersections['location']:  
                    #print(location)
                    mrks.append(location)

#print(mrks)
twin = []
for i in range(0, len(mrks),2):
    twin.append(str(mrks[i])+'___'+str(mrks[i+1]))
print('points ___________________________________________________')   
for points in twin:
    print(points)

Answer 1

它似乎使用JavaScript從 API 獲取數據作為 JSON 並在 memory（帶有gpx數據的blob ）中創建數據，當您單擊它時，它會直接從 memory 發送數據（ blob ） - 所以沒有 886026588 當我使用click()時，它會詢問文件夾，這需要手動單擊。

似乎獲得JSON比gpx更簡單
而url到JSON數據也用-0.0898,51.514739;-0.096656,51.516214

---

編輯：鏈接到 web 頁面使用經緯度lat,lon但鏈接到 JSON 需要lon,lat

---

import requests

start_lon = -0.0898    # can be also as text
start_lat = 51.514739  # can be also as text

end_lon = -0.096656    # can be also as text
end_lat = 51.516214    # can be also as text

data = f"{start_lon},{start_lat};{end_lon},{end_lat}"

transport = 'bike'  # 'car', 'foot'

url = f'https://routing.openstreetmap.de/routed-{transport}/route/v1/driving/{data}'

payload = {
    'overview': 'false',     # can't be True/False
    'alternatives': 'true',  # can't be True/False
    'steps': 'true',         # can't be True/False
}

response = requests.get(url, params=payload)
print(response.url)
#print(response.text)
print('---')

data = response.json()

for point in data['waypoints']:
    print('name:', point['name'])
    print('distance:', point['distance'])
    print('location:', point['location'])
    print('---')

結果：

url: https://routing.openstreetmap.de/routed-bike/route/v1/driving/-0.0898,51.514739;-0.096656,51.516214?overview=false&alternatives=true&steps=true
---
name: Princes Street
distance: 4.955845
location: [-0.089734, 51.514722]
---
name: Gresham Street
distance: 8.8597
location: [-0.096605, 51.516287]
---

---

編輯：

路由和 python 模塊的一些文檔PyrouteLib , SimpleOsmRouter