[英]MS Access / SQL Server - VBA: Upload local file to filestream on remote SQL server
我需要大約每周一次將文件(<10 MB)上傳到 same.network 中遠程服務器上的 SQL Server 2016 數據庫。 到目前為止,它都在 Access FE/BE 中,但我想遷移到 SQL 服務器作為后端。
我在 MS Access 中的附件現在需要在 SQL 數據庫上處理,因為我不想在文件共享上執行此操作。
我從SQLShack中找到了很多關於使用類似東西的線程
DECLARE @File varbinary(MAX);
SELECT
@File = CAST(bulkcolumn AS varbinary(max))
FROM
OPENROWSET(BULK 'C:\sqlshack\akshita.png', SINGLE_BLOB) as MyData;
INSERT INTO DemoFileStreamTable_1
VALUES (NEWID(), 'Sample Picture', @File)
當我在 SQL 服務器本身上的 SSMS 中啟動查詢並且該文件已可由服務器在其本地驅動器上訪問時,此方法有效。
但是,當我嘗試將其放入 Access 前端計算機上的 VBA 代碼中時:
Sub DaoOdbcExample()
Dim cdb As DAO.Database, qdf As DAO.QueryDef
Set cdb = CurrentDb
Set qdf = cdb.CreateQueryDef("")
qdf.Connect = "ODBC;" & _
"Driver={SQL Server};" & _
"Server=MyServer;" & _
"Database=MyDatabase;" & _
"Trusted_Connection=yes;"
qdf.SQL = "DECLARE @File varbinary(MAX); SELECT @File = CAST(bulkcolumn as varbinary(max)) FROM OPENROWSET(BULK 'D:\SomeFile.pdf', SINGLE_BLOB) as MyData; INSERT INTO DemoFileStreamTable_1 VALUES ( NEWID(), 'Test PDF', @File)"
qdf.ReturnsRecords = False
qdf.Execute dbFailOnError
Set qdf = Nothing
Set cdb = Nothing
End Sub
我只是得到一個錯誤
ODBC--調用失敗
其他簡單的“選擇”語句似乎有效,因此連接本身似乎沒問題。
所以我的問題是:
如何使用 MS Access 作為我的前端,將計算機 A 上的本地文件上傳到計算機 B 上的遠程 SQL 服務器(無法直接訪問該文件)?
有沒有不使用“BULK”語句的不同方法,因為我需要所有用戶的“bulkadmin”權限?
我可能已經使用來自@AlwaysLearning 的鏈接找到了解決方案。 第一個子實際上回答了我將文件上傳到遠程 FILESTREAM SQL 服務器的問題。 第二個 sub 將所有上傳的文件下載到給定目錄中。
Private Sub btn_AddAtachment_Click()
Dim cn, rs As Object
Dim sql, strCnxn, FileToUpload, FileName As String
'FileSystemObject to do so some file checks
Dim fso As Object
Set fso = VBA.CreateObject("Scripting.FileSystemObject")
'select file to upload, will open a FileOpenDialog
FileToUpload = CustOpenFileDialog
If FileToUpload <> "" Then
FileName = fso.GetFileName(FileToUpload) 'get only filename + extension
'SQL Connection
strCnxn = "Provider=sqloledb;" & _
"Data Source=MYSERVER;" & _
"Initial Catalog=MYDATABASE;" & _
"Integrated Security=SSPI;" 'Windows-Authentication
Set cn = CreateObject("ADODB.Connection")
cn.Open strCnxn
'Recordset
sql = "DemoFileStreamTable_1" 'Table to add file
Set rs = CreateObject("ADODB.Recordset")
rs.Open sql, strCnxn, 1, 3 '1 - adOpenKeyset, 3 - adLockOptimistic"
'Create Stream to upload File as BLOB data
Dim strm As Object
Set strm = CreateObject("ADODB.Stream")
strm.Type = 1 '1 - adTypeBinary
strm.Open
strm.LoadFromFile FileToUpload
'Insert into database
rs.AddNew 'FileId will be automatically handled by SQL
rs!File = strm.Read
rs!FileName = FileName
strm.Close
rs.Update
End If
End Sub
Private Sub btn_DwnldSQL_Click()
Dim cn, rs As Object
Dim sql As String
Dim oStream As Object
Dim OutputPath, strCnxn, FileName, SaveLocation As String
OutputPath = "D:\ExportTest"
'FileSystemObject to do so some file checks
Dim fso As Object
Set fso = VBA.CreateObject("Scripting.FileSystemObject")
'SQL Connection
Set cn = CreateObject("ADODB.Connection")
strCnxn = "Provider=sqloledb;" & _
"Data Source=MYSERVER;" & _
"Initial Catalog=MYDATABASE;" & _
"Integrated Security=SSPI;" 'Windows-Authentication
cn.Open strCnxn
'your sql statment including varbinary max field here it is File
sql = " SELECT [File],[FileName] from [DemoFileStreamTable_1] "
'Recordset
Set rs = CreateObject("ADODB.Recordset")
rs.Open sql, cn
'Actual Download
Do Until rs.EOF 'Read all rows
Set oStream = CreateObject("ADODB.Stream")
FileName = CStr(rs.Fields("FileName").Value) 'FileName from Database field
SaveLocation = fso.BuildPath(OutputPath, FileName) 'Create outputpath
With oStream
.Type = 1 '1 - adTypeBinary
.Open
.Write rs.Fields("File").Value 'actual BLOB data
.SaveToFile SaveLocation, 2 '2 - adSaveCreateOverWrite
.Close
End With
Set oStream = Nothing
rs.MoveNext
Loop
rs.Close
cn.Close
End Sub
Function CustOpenFileDialog() As String
Const msoFileDialogFilePicker As Long = 3
Dim objDialog As Object
Set objDialog = Application.FileDialog(msoFileDialogFilePicker)
Dim fso As Object
Set fso = VBA.CreateObject("Scripting.FileSystemObject")
Dim FileName As String
With objDialog
.AllowMultiSelect = False
' Set the title of the dialog box.
.Title = "Please select one file"
' Clear out the current filters, and add our own.
.Filters.Clear
.Filters.Add "supported Types", "*.pdf, *.xml, *.gltf, *.jpg, *.png"
' Show the dialog box. If the .Show method returns True, the
' user picked at least one file. If the .Show method returns
' False, the user clicked Cancel.
If .Show = True Then
CustOpenFileDialog = .SelectedItems(1)
Else
CustOpenFileDialog = ""
End If
End With
End Function
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