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[英]How to go to next page until the last page in Python Selenium when scraping website?
[英]How to stop the selenium webdriver after reaching the last page while scraping the website?
網站上的數據量(頁數)不斷變化,我需要通過分頁循環抓取所有頁面。 網址: https://monentreprise.bj/page/annonces
我試過的代碼:
xpath= "//*[@id='yw3']/li[12]/a"
while True:
next_page = driver.find_elements(By.XPATH,xpath)
if len(next_page) < 1:
print("No more pages")
break
else:
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.XPATH, xpath))).click()
print('ok')
ok
連續打印
因為條件if len(next_page)<1
總是 False。
例如,我嘗試了 url monentreprise.bj/page/annonces?Company_page=9999999999999999999999 ,它給出了第 13 頁,即最后一頁
這里有幾個問題:
//*[@id='yw3']/li[12]/a
不是next
分頁按鈕的正確定位器。.pagination.next
包含disabled
的 class。from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import time
driver = webdriver.Chrome()
my_url = "https://monentreprise.bj/page/annonces"
driver.get(my_url)
next_page_parent = '.pagination .next'
next_page_parent_arrow = '.pagination .next a'
while True:
driver.execute_script("window.scrollTo(0, document.body.scrollHeight)")
time.sleep(0.5)
parent = driver.find_element(By.CSS_SELECTOR,next_page_parent)
class_name = parent.get_attribute("class")
if "disabled" in class_name:
print("No more pages")
break
else:
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, next_page_parent_arrow))).click()
time.sleep(1.5)
print('ok')
output 是:
ok
ok
ok
ok
ok
ok
ok
ok
ok
ok
ok
ok
ok
No more pages
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