Java 相當於這個 JavaScript 正則表達式代碼？

Question

我有這個 JavaScript 代碼：

highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replace(/[\\;]/g, ' ');
highlightTerm = highlightTerm.replace(/([{}<>\/=:])(?=(?:[^"]|"[^"]*")*$)/g, '\\$&');
highlightTerm = highlightTerm.replace(/"/g, '\"');
highlightTerm = highlightTerm.trim();

console.log(highlightTerm); // "h\=e ?l*l\{o"

我正在嘗試找到等效的 Java。 我嘗試了以下位它給出了不同的結果：

String highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replaceAll("[\\;]", " ");
highlightTerm = highlightTerm.replaceAll("([{}<>\\/=:])(?=(?:[^\"]|\"[^\"]*\")*$)", "\\$&");
highlightTerm = highlightTerm.replaceAll("[\"]", "\\\"");
highlightTerm = highlightTerm.trim();

System.out.println(highlightTerm); // "h=e ?l*l{o"

任何幫助深表感謝！

Answer 1

你遇到的問題是'\\$&'是 Javascript 表示整個匹配的字符串，但在 Java 中並不意味着相同。我認為 Java 中沒有單行解決方案來解決這個問題，但是這個代碼應該工作：

String highlightTerm = "h=e;?l*l{o";
highlightTerm = highlightTerm.replaceAll("[\\;]", " ");
//highlightTerm = highlightTerm.replace(/([{}<>\/=:])(?=(?:[^"]|"[^"]*")*$)/g, '\\$&');

//These lines are replacement for the above line
Pattern pattern = Pattern.compile("([{}<>\\/=:])(?=(?:[^\"]|\"[^\"]*\")*$)");
Matcher matcher = pattern.matcher(highlightTerm);

StringBuilder builder = new StringBuilder();
int i = 0;
while (matcher.find()) {
    String replacement = "\\" + matcher.group(1);
    builder.append(highlightTerm, i, matcher.start());
    builder.append(replacement);
    i = matcher.end();
}
builder.append(highlightTerm.substring(i));
highlightTerm = builder.toString();

//rest of your code
highlightTerm = highlightTerm.replaceAll("[\"]", "\\\"");
highlightTerm = highlightTerm.trim();

System.out.println(highlightTerm);