[英]How can I write every list from a nested list separately to a file?
我正在嘗試將嵌套列表中的每個列表寫入同一個文件。 但是我希望每個列表都以換行符開頭。
我做了這個並且它有效,但它非常低效並且看起來很糟糕:
appendFile "scraped.txt" (show (take 1 l))
appendFile "scraped.txt" ("\n")
let l3 = (drop 1 l)
appendFile "scraped.txt" (show (take 1 l3))
appendFile "scraped.txt" ("\n")
let l4 = (drop 1 l3)
appendFile "scraped.txt" (show (take 1 l4))
appendFile "scraped.txt" ("\n")
let l5 = (drop 1 l4)
appendFile "scraped.txt" (show (take 1 l5))
appendFile "scraped.txt" ("\n")
let l6 = (drop 1 l5)
appendFile "scraped.txt" (show (take 1 l6))
appendFile "scraped.txt" ("\n")
我嘗試了類似下面的操作,但我似乎無法正確使用映射 function:
listValues :: [[String]] -> [String]
listValues :: (map . map)
appendValues :: [[String]] -> IO ()
appendValues = appendFile "scraped.txt" listValues
txt 文件現在看起來像這樣,沒關系,我只是想知道如何改進我的代碼並學習如何使用映射 function。
Title,Subtitle,Date,Author
[["Een gezonde samenleving? \226\128\156Het belang van sporten wordt onderschat\226\128\157","Teamsport","16 maart 2022","HAN redactie"]]
[["Zo vader, zo dochter","Carsten en Kirsten","10 maart 2022","HAN redactie"]]
[["Milieuvriendelijk vervoer met waterstof","Kennisclip","09 maart 2022","HAN redactie"]]
[["\"Ik heb zin in wat nog komen gaat\"","Master Mind","08 maart 2022","HAN redactie"]]
[["Oorlog in Oekra\195\175ne","Statement van het CvB","07 maart 2022","HAN redactie"]]
要在類似地圖的循環中執行此操作,您通常會使用mapM_
庫 function 。 function 名稱中的最后一個下划線 _ 表示操作結果被忽略,這很適合我們,因為我們想要IO ()
的結果類型。
獲取文件句柄似乎是合適的,以避免要求操作系統重復重新打開同一個 output 文件,這是一種浪費。
可能的代碼:
import System.IO
type FileName = String
writeNestedList :: Show a => FileName -> [[a]] -> IO ()
writeNestedList fileName xss =
do
fh <- openFile fileName WriteMode -- get a file handle
mapM_ ((hPutStrLn fh) . show) xss
hClose fh
main :: IO ()
main = do
let xss = [ ["ab","bc"] ,["de","ef"], ["gh","hi"] ]
writeNestedList "scraped.txt" xss
$
$ ghc q71608762.hs -o q71608762.x
[1 of 1] Compiling Main ( q71608762.hs, q71608762.o )
Linking ./q71608762.x ...
$
$ q71608762.x
$
$ cat scraped.txt
["ab","bc"]
["de","ef"]
["gh","hi"]
$
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