Python 中列表 output 的自定義格式

Question

我已經審查了其他問題，但沒有具體找到這個答案。 我正在制作一個程序來讀取包含多行數據的文本文件，並量化相似的行。 下面是我正在使用的代碼，但我正在嘗試以自定義格式或至少單獨打印 output。 我該如何改進？

理想情況下，我想要一個 output，例如：

B12-H-BB-DD: x3
A2-W-FF-DIN: x2
A2-FF-DIN: x1
C1-GH-KK-LOP: x1

import collections
a = "test.txt"
line_file = open(a, "r")
print(line_file.readable()) #Readable check.
print(line_file.read()) #Prints each individual line.

#Code for quantity counter.
counts = collections.Counter() #Creates a new counter.
with open(a) as infile:
    for line in infile:
        for number in line.split():
            counts.update((number,))
print(counts) #How can I print these on separate lines, with custom format?

line_file.close()

Answer 1

counts = {}
with open('file.txt') as f:
    for line in f:
        line = line.strip()
        counts[line] = counts.get(line, 0) + 1

print(counts)

counts.get(line, 0)如果給定鍵在結果字典中不存在則返回0 。

Output：

{'B12-H-BB-DD': 3, 'A2-W-FF-DIN': 2, 'A2-FF-DIN': 1, 'C1-GH-KK-LOP': 1}

特殊格式：

for key, count in counts.items():
    print(f"{key}: x{count}")

Output：

B12-H-BB-DD: x3
A2-W-FF-DIN: x2
A2-FF-DIN: x1
C1-GH-KK-LOP: x1

使用來自 collections 的計數器的更多 Pythonic 方式：

from collections import Counter

with open('file.txt') as f:
    lines = [line.strip() for line in f]
counts = Counter(lines)

for key, count in counts.items():
    print(f"{key}: x{count}")