如何從打印列表中刪除括號？

Question

上下文：用戶輸入員工姓名、工作時間和小時工資。 Output 應該是輸入的名字，以及他們的總工資。 例如：“約翰 300 美元”。 問題是我所擁有的只是輸出 ('john', 300.0)

payroll = 0
employee_list = []
print('Enter Information ( Name, hours worked, hourly rate) seperated by commas')
print('Press Enter to stop Enetering Employee Information')
info = input('Enter Employee Information: ')

while info != '':
    employee_info = info.split(',')
    hours_worked = float(employee_info[1])
    hourly_rate = float(employee_info[2])
    employee_name = employee_info[0].strip()
    employee_info = [employee_name, (hours_worked * hourly_rate)]
    employee_list.append(employee_info)
    payroll += hours_worked * hourly_rate
    info = input('Enter Employee Information: ')
    
print()
print('Total Payroll ${:.2f}'.format(payroll))
print()
print('Employees with Paychecks')
for i in range(len(employee_list)):
    print(employee_list[i])

Answer 1

正如其他人已經指出的那樣，最好的選擇（也是最現代的方法）是使用 f 弦。 f 弦是在 Python 3.6 中引入的。

for i in range(len(employee_list)):
    print(f"{employee_list[i][0]}: ${employee_list[i][1]}")

我想指出一些題外話以外的事情。 如果可以使用集合控制循環，請避免模仿計數控制循環。 這使您的代碼更具可讀性：

for employee_info in employee_list:
    print(f"{employee_info[0]}: ${employee_info[1]}")

---

from collections import namedtuple

EmployeeInfo = namedtuple("EmployeeInfo", ["name", "total"])

def parse_input(info: str) -> EmployeeInfo:
    name, hours, rate = info.split(",")
    return EmployeeInfo(name.strip(), float(hours)*float(rate))

employee_info_list = []

print("Enter Information (name, hours worked, hourly rate) separated by commas")
print("Press Enter to stop Entering Employee Information")

while True:

    employee_input = input("Enter Employee Information: ")

    if not employee_input:
        break

    employee_info = parse_input(employee_input)

    employee_info_list.append(employee_info)
    
payroll = sum(employee_info.total for employee_info in employee_info_list)

print()
print(f"Total Payroll: ${payroll:.2f}")
print()
print("Employees with Paychecks:")

for employee_info in employee_info_list:
    print(f"{employee_info.name}: ${employee_info.total}")

Answer 2

print('{} ${}'.format(*employee_list[i]))

Answer 3

聽起來您得到的元組為 output。您可以使用 f 字符串來格式化該變量，方法是調用大括號內的每個項目，並使用以“f”開頭的字符串。 例如：

tuple = ('text', 100)
print(f'{tuple[0]} ${tuple[1]}')

output: text $100

您可以在輸入 output 或 pep-498 的 python 文檔中閱讀更多信息： https://peps.python.org/pep-0498/

Answer 4

f-strings 是你的朋友：

payroll = 0
employee_list = []
print('Enter Information ( Name, hours worked, hourly rate) seperated by commas')
print('Press Enter to stop Enterting Employee Information')
info = 'Billy, 1234.3, 42' # input('Enter Employee Information: ')

while info != '':
    process = lambda x, y, z: [x.strip(), float(y), float(z)]
    employee_name, hours_worked, hourly_rate = process(*info.split(','))  
    employee_list.append(f'{employee_name}, ${hours_worked * hourly_rate:.2f}')
    payroll += hours_worked * hourly_rate
    info = '' # input('Enter Employee Information: ')
    
print()
print(f'Total Payroll ${payroll:.2f}')
print()
print('Employees with Paychecks')
for i in range(len(employee_list)):
    print(employee_list[i])

Output：

Enter Information ( Name, hours worked, hourly rate) seperated by commas
Press Enter to stop Enterting Employee Information

Total Payroll $51840.60

Employees with Paychecks
Billy, $51840.60

Answer 5

在你的最后一行：

for i in range(len(employee_list)):
    print(*employee_list[i], sep=",")

1個

*打開列表或元組打印 arguments

2個

通過sep參數，設置在控制台中如何將值彼此分開

Answer 6

用表情打印

for i in range(len(employee_list)):
    print(F"{employee_list[i][0]}, {employee_list[i][1]}")