[英]how to change child component state in reactjs
我遇到了以下問題:我需要在組件內部使用另一個組件的 function:
header.js
export default function Header() {
const [showModalLogin ,setShowModalLogin] = useState(false);
return(
<>
<span>Hi, <Link onClick={() =>{ setShowModalLogin(true)}}>login</Link> </span>
{showModalLogin ? <LoginModal setShowModalLogin={setShowModalLogin}/> : ''}
</>
);
}
主頁.js
import Header from '../../components/header/header';
export default function Home() {
return (
<>
<Header />
<Link onClick={() =>{ setShowModalLogin(true)}}>open login</Link>
</>
}
如何在home.js中調用header.js中的setShowModalLogin function? 我也在嘗試使用上下文api,但我仍然無法解決它。
您可以將 useState 放在 Header 組件中並將 setShowModalLogin 作為道具傳遞:
import Header from '../../components/header/header';
export default function Home() {
const [isShowModalLogin ,setShowModalLogin] = useState(false);
return (
<>
<Header isShowModalLogin={isShowModalLogin} setShowModalLogin={setShowModalLogin} />
<Link onClick={() => setShowModalLogin(true)}>open login</Link>
</>
}
export default function Header({ isShowModalLogin, setShowModalLogin }) {
return(
<>
<span>Hi, <Link onClick={() => setShowModalLogin(true)}>login</Link> </span>
{isShowModalLogin ? <LoginModal setShowModalLogin={setShowModalLogin}/> : ''}
</>
);
}
然后你可以這樣做:
export const YourContext = createContext();
export const YourProvider = ({ children }) => {
const [isShowModalLogin, setShowModalLogin] = useState(false);
const value = {
isShowModalLogin,
setShowModalLogin
};
return <YourContext.Provider value={value}>{children}</YourContext.Provider>;
}
// App.js
const App = () => {
return (
<YourProvider>
<AppContent />
</YourProvider>
)
}
所以現在你可以像這里一樣使用它:
import Header from '../../components/header/header';
export default function Home() {
const { isShowModalLogin, setShowModalLogin } = useContext(YourContext);
return (
<>
<Header isShowModalLogin={isShowModalLogin} setShowModalLogin={setShowModalLogin} />
<Link onClick={() => setShowModalLogin(true)}>open login</Link>
</>
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.