[英]SQL query with count distinct using multiple columns
SQL服務器中有下表:
create table [dbo].[stats](
[customerid] [int] NOT NULL,
[username] [nvarchar](256) NOT NULL,
[source] [int] NOT NULL,
[destination] [int] NOT NULL,
[date] [smalldatetime] NOT NULL
)
填充數據:
customerid username source destination date
1 user1 1 1 2022-05-06 00:00:00
1 user2 2 1 2022-05-06 00:00:00
1 user21 1 2 2022-05-06 00:00:00
有沒有一種方法可以創建一個查詢來顯示有多少唯一用戶使用了每個 customerid 的每種類型的源和目標?
使用上面的示例,我想要以下 output:
customerid source1 source2 destination1 destination2
1 2 1 2 1
偽查詢:
select customerid,
count(distinct(username + source)) where source = 1) as source1,
count(distinct(username + source)) where source = 2) as source2,
count(distinct(username + destination)) where destination = 1) as destination1,
count(distinct(username + destination)) where destination = 2) as destination2,
from stats
group by customerid
你可以用例
select
customerid,
count(distinct(case
when source = 1
then username
End)) as source1,
count(distinct(case
when source = 2
Then username
End )) as source2,
count(distinct(case
when destination = 1
Then username
End)) as destination1,
count(distinct(case
when destination = 2
Then username
End)) as destination2,
from stats
group by customerid;
select userID, source, destination, count(*)
from stats
group by userID, source, destination
看起來你只需要一個條件計數
select customerid,
Count(case when source=1 then 1 end) Source1,
Count(case when source=2 then 1 end) Source2,
Count(case when destination=1 then 1 end) destination1,
Count(case when destination=2 then 1 end) destination2
from stats
group by customerid;
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