[英]Intersection of an array with a deeply nested object in javascript
我想包含數組中存在的對象的所有鍵並丟棄其余鍵,例如,如果我有一個數組,
const arr = ['apple', 'milk', 'bread', 'coke'];
和一個對象,
const dummy = {
apple: {
category: 'fruit'
},
banana: {
category: 'fruit'
},
potato: {
category: 'vegetable'
},
dairy: {
milk: {
type: 'A2'
}
},
bakery: {
bread: {
type: 'brown'
}
},
beverage: {
cold_drink: {
coke: {
type: 'diet'
},
beer: {
}
}
}
}
我希望我的結果對象僅包含來自arr
的鍵,無論是直接鍵還是深度嵌套。 所以對於上述情況,我的結果對象看起來像,
{
apple: {
category: 'fruit'
},
dairy: {
milk: {
type: 'A2'
}
},
bakery: {
bread: {
type: 'brown'
}
},
beverage: {
cold_drink: {
coke: {
type: 'diet'
},
beer: {}
}
}
}
我試圖通過遞歸解決這個問題,但無法正確獲得輸出。 下面是我的代碼,你能幫我解決我哪里出錯了嗎?
function fetchResultantObject(object, key, result) {
if(typeof object !== 'object')
return null;
for(let objKey in object) {
if(key.indexOf(objKey) > -1) {
result[objKey] = object[objKey];
} else {
result[objKey] = fetchValueByKey(object[objKey], key, result);
}
}
return result;
}
console.log(fetchResultantObject(dummy, arr, {}));
您可以過濾條目並檢查(嵌套)對象是否包含想要的鍵。
const hasKey = object => object && typeof object === 'object' && (keys.some(k => k in object) || Object.values(object).some(hasKey)), keys = ['apple', 'milk', 'bread', 'coke'], data = { apple: { category: 'fruit' }, banana: { category: 'fruit' }, potato: { category: 'vegetable' }, dairy: { milk: { type: 'A2' } }, bakery: { bread: { type: 'brown' } }, beverage: { cold_drink: { coke: { type: 'diet' } } } }, result = Object.fromEntries(Object .entries(data) .filter(([k, v]) => hasKey({ [k]: v })) ); console.log(result);
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