[英]Laravel Subquery with Query Builder
我有一個這樣的 MySQL 查詢:
SELECT
a.id,
a.nip,
a.name,
COUNT(
(
SELECT id
FROM covis_transactions
WHERE user_id = a.id
)
) AS total_survey
FROM users a
WHERE a.user_role_id = 7
GROUP BY a.id
我嘗試將其轉換為 Eloquent 查詢,但這似乎不起作用:
DB::table('users as a')
->selectRaw("a.id, a.nip, a.name, COUNT(".DB::table('covis_transactions')->where('user_id', 'a.id').") as total_survey")
->where('a.user_role_id', 7)
->groupBy('a.id')
->get();
您應該在您的User
模型和covis_transactions
表的模型之間創建關系。 (我將其稱為CovisTransaction
)
# User.php
public function covis_transactions()
{
return $this->hasMany(CovisTransaction::class);
}
然后,您可以使用withCount
來獲取聚合計數。
User::query()
->select('id', 'nip', 'name')
->withCount('covis_transactions as total_survey')
->where('user_role_id', 7)
->groupBy('id')
->get();
您可以將子查詢從構建器轉換為字符串:
DB::table('covis_transactions')->where('user_id', 'a.id')
DB::table('covis_transactions')->where('user_id', 'a.id')->toSql()
試試看 :
DB::table('users as a')
->selectRaw("a.id, a.nip, a.name, COUNT(" . DB::table('covis_transactions')->where('user_id', 'a.id')->toSql() . ") as total_survey")
->where('a.user_role_id', 7)
->groupBy('a.id')
->get();
或者可以使用join
然后 count( covis_transactions
. id
)
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