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我們如何單擊 Python Selenium 中的列表圖標（“列表”對象沒有屬性“單擊”錯誤）？

[英]How can we click on an icon which is list in Python Selenium ('list' object has no attribute 'click' error)?

 原文  2022-05-12 11:19:53  2   2    python/ selenium/ rpa

問題描述

我正在進行一個 RPA 項目，我正在嘗試通過網站進行自動化。 我正在嘗試編寫 xpad 以單擊我瞄准的對象（使用硒），但它是一個列表，我收到此錯誤； ''list' 對象沒有屬性 'click'' 我將檢查部分的圖像 (ss) 粘貼到此處和代碼下方。

site = webdriver.Chrome("D:\\Users\\user\\Desktop\\chromedriver.exe")
site.get("websiteaddress")
site.find_elements_by_partial_link_text('Findings and Action').click()

最后一行也是這個

fa = site.find_elements_by_xpath("//ul[@class='sasLeftNavNav']//li[.//span[text()='RGF_HUB_Home_MRM_appContainer_lfn_5_icn']]/li[@id='RGF_HUB_Home_MRM_appContainer_lfn_5']")
fa.click()

提前感謝您的幫助！

從瀏覽器檢查（部分）： 

 <li id="RGF_HUB_Home_MRM_appContainer_lfn_5" role="menuitem" data-item="5" aria-label="Selected, Findings and Action" tabindex="0" class="sasLeftNavItemSelected" aria-selected="true"><span id="RGF_HUB_Home_MRM_appContainer_lfn_5_icn" data-sap-ui="RGF_HUB_Home_MRM_appContainer_lfn_5_icn" data-item="5" role="presentation" aria-hidden="true" aria-label="Findings and Action" title="Findings and Action" data-sap-ui-icon-content="" class="sapUiIcon" style="font-family:'sas-icons'"></span><span class="sasLeftNavItemState" id="RGF_HUB_Home_MRM_appContainer_lfn_5_state" data-item="5"></span><span class="sasLeftNavItemLabel" title="Findings and Action" data-item="5">Findings and Action</span></li> <span id="RGF_HUB_Home_MRM_appContainer_lfn_5_icn" data-sap-ui="RGF_HUB_Home_MRM_appContainer_lfn_5_icn" data-item="5" role="presentation" aria-hidden="true" aria-label="Findings and Action" title="Findings and Action" data-sap-ui-icon-content="" class="sapUiIcon" style="font-family:'sas-icons'"></span> <::before></::before>

在此處輸入圖像描述

2 個解決方案

解決方案1
 0  2022-05-12 11:23:43

find_elements_by_partial_link_text()函數返回所有找到的元素的列表。 如果您只需要一個元素，您可以使用find_element_by_partial_link_text()函數。

但是，如果您需要單擊找到與您的定位器匹配的所有元素，則可以使用：

for element in site.find_elements_by_partial_link_text('Findings and Action'):
    element.click()

解決方案2
 0  2022-05-17 18:41:14

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