flask 應用程序和 mysql pythonanywhere 中的事務錯誤

Question

當我嘗試登錄或注冊時，我通常會收到此錯誤，“mysql.connector.errors.OperationalError: 2013 (HY000): Lost connection to MySQL server during query”

這發生在非本地托管的 pythonanywhere 中。

當我更新超時時它工作一次並且在第二次請求錯誤再次顯示

對這個問題有什么想法嗎？

這就是我的代碼鎖定方式：

import mysql.connector

db_connection = mysql.connector.connect(
                    host='stuttering.mysql.pythonanywhere-services.com', user='......',
                    passwd='.......', database='stuttering$stutter',
                    connect_timeout=15000 ,
                    )

db_cursor = db_connection.cursor(buffered=True)


def insertuser(first_name, last_name, email, password):
    db_cursor.execute('INSERT INTO users (first_name, last_name, email, password) VALUES(%s, %s, %s,%s)',
                      (str(first_name), str(last_name), str(email), str(password)))
    db_connection.commit()
    return True


def signin(email, password):
    result = ""
    db_cursor.execute('select email ,password from users where email=%s and password=%s', (str(email), str(password)))
    for sign in db_cursor:
        result = sign[0]
    if result != "":
        db_connection.commit()
        return 1
    else:
        db_connection.commit()
        return 0


def update_password(email, password):
    sql = 'update users set password=%s where email=%s'
    value = (str(password), str(email))
    db_cursor.execute(sql, value)
    db_connection.commit()
    return True


def update_info(first_name, last_name, email, psw):
    sql = 'update users set password=%s, first_name=%s, last_name=%s where email=%s'
    value = (str(psw), str(first_name), str(last_name), str(email))
    db_cursor.execute(sql, value)
    db_connection.commit()
    return True


def get_userdata(email, psw):
    db_cursor.execute('SELECT * FROM users WHERE email = %s AND password = %s', (email, psw,))
    account = db_cursor.fetchone()
    db_connection.commit()
    return account

def delete_user(email):
    db_cursor.execute('DELETE FROM users where email = %s', (email,))
    account = db_cursor.fetchone()
    db_connection.commit()
    return account

def get_record_number(id):
    db_cursor.execute('SELECT count( * ) FROM audio_data WHERE id =%s', (id,))
    x = db_cursor.fetchone()
    db_connection.commit()
    return x


def insert_audio_data(id, audio_path, created_at):
    db_cursor.execute('INSERT INTO audio_data (id, audio_path, created_at) VALUES(%s, %s, %s)',
                      (id, audio_path, created_at))
    db_connection.commit()


def insert_score(audio_path, score):
    db_cursor.execute('UPDATE audio_data set score=%s WHERE audio_path=%s', (str(score), audio_path))
    db_connection.commit()


def get_graph_data(id):
    print("id")
    print(id)
    db_cursor.execute('SELECT sum(score),COUNT(score) FROM audio_data WHERE id=%s GROUP BY DATE(created_at)', (id,))
    x = db_cursor.fetchall()
    if len(x) == 0:
        return 0
    if None in x[0]:
        db_connection.commit()
        return 0
    else:
        y = [float(i[0] / i[1]) for i in x]
        db_cursor.execute('SELECT DISTINCT DATE(created_at) FROM audio_data WHERE id=%s AND score IS NOT NULL', (id,))
        dt = db_cursor.fetchall()
        if None in dt[0]:
            db_connection.commit()
            return 0
        else:
            dt = [w[0] for w in dt]
            db_connection.commit()
            return y, dt

Answer 1

不要在導入時創建連接，否則它將超時並且不可用。 在視圖代碼中創建與數據庫的連接，因此每次需要時都有一個新連接。