嘗試使用 javascript 從三個現有對象創建一個新對象

Question

我有三個對象，每個對象都是從 Django-rest 框架序列化的。 每個對象都是配置文件中用戶的數組。 每個配置文件都需要一個 org_id 和電子郵件才能有效。 "activeUsers" 和 "inactiveUsers" 永遠不會有重復，每個元素共享相同的 org_id，並且 user_id 和 email 總是不同的。 “nonProfileUsers”是排除的所有其他配置文件
"activeUsers" 和 "inactiveUsers" org_id，注意 user_id 和 email 可以並且將會出現不止一次。

 activeUsers = [
    { "org_id": 1, "user_id": 9, "firstName": "Joj", "lastName": "Blonde", "email": "bop@test.ca", },
    {"org_id": 1, "user_id": 1, "firstName": "Tyler", "lastName": "Whitfield", "email": "tyler@atg.net", },
  ]

inactiveUsers = [
  {  "org_id": 1, "user_id": 3, "firstName": "James", "lastName": "Bond", "email": "test@test.ca", },
  {"org_id": 1, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", }
]

//user that are in different profiles
nonProfileUsers = [
  { "org_id": 2, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", },
  {  "org_id": 3, "user_id": 6, "firstName": "weak", "lastName": "jdf", "email": "not@not.ca", },
  {  "org_id": 3, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", },
  {  "org_id": 4, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", },
  {  "org_id": 3, "user_id": 3, "firstName": "James", "lastName": "Bond", "email": "test@test.ca", },
  {  "org_id": 2, "user_id": 5, "firstName": "test", "lastName": "test", "email": "tester@tester.ca", },
  { "org_id": 2, "user_id": 3, "firstName": "James", "lastName": "Bond", "email": "test@test.ca", },
]

我正在使用 java 腳本，我需要做一些事情。 縮小“nonProfileUsers”以刪除重復的 user_id 和 email 組合，但至少保留一個 org_id（保留哪一個無關緊要）

scaledNonProfileUsers = [
          { "org_id": 2, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", },
          {  "org_id": 3, "user_id": 6, "firstName": "weak", "lastName": "jdf", "email": "not@not.ca", },
          {  "org_id": 2, "user_id": 5, "firstName": "test", "lastName": "test", "email": "tester@tester.ca", },
          { "org_id": 2, "user_id": 3, "firstName": "James", "lastName": "Bond", "email": "test@test.ca", },
        ]

結合了“activeUsers”和“inactiveUsers”——我能夠完成第 2 步

 combinedUsers= [
        { "org_id": 1, "user_id": 9, "firstName": "Joj", "lastName": "Blonde", "email": "bop@test.ca", },
        {"org_id": 1, "user_id": 1, "firstName": "Tyler", "lastName": "Whitfield", "email": "tyler@atg.net", },
        {  "org_id": 1, "user_id": 3, "firstName": "James", "lastName": "Bond", "email": "test@test.ca", },
       {"org_id": 1, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", }
      ]

通過比較“scaledNonProfileUsers”與“combinedUsers”創建一個新對象。 “scaledNonProfileUsers”中而不是“combinedUsers”中的電子郵件將成為最終對象。

finalObj= [
            {  "org_id": 3, "user_id": 6, "firstName": "weak", "lastName": "jdf", "email": "not@not.ca", },
            {  "org_id": 2, "user_id": 5, "firstName": "test", "lastName": "test", "email": "tester@tester.ca", },
          ]

  

我真的在第 1 步和第 3 步苦苦掙扎。

如果我只隔離電子郵件，我可以像這樣制作一個數組

[
    0:"non@not.ca",
    1:"tester@tester.ca"
  ]

但我需要至少包含一個 org_id 和電子郵件。

到目前為止，這段代碼一直是我的方法。

const temp_active = [...inactiveUsers, ...activeUsers,]// master list of both active/inactive

  const scaledNonProfileUsers= []//isolate email and make a list of emails
  for (var i = 0; i < nonProfileUsers?.length; i++) {
    scaledNonProfileUsers.push(nonProfileUsers[i]?.email)
  }

  const combinedUsers= []//isolate email and make a list of emails
  for (var i = 0; i < temp_active?.length; i++) {
   combinedUsers.push(temp_active[i]?.email)
  }

  let combinedUsers_filter = combinedUsers.filter((c, index) => {//filter duplicated emails
    return combinedUsers.indexOf(c) === index;
  });
  let scaledNonProfileUsers_filter = scaledNonProfileUsers.filter((c, index) => {//filter duplicate emails
    return scaledNonProfileUsers.indexOf(c) === index;
  });

  var finalObj = [];
  for (var i = 0; i < scaledNonProfileUsers_filter?.length; i++) {
    if (!eleContainsInArray(combinedUsers_filter, scaledNonProfileUsers_filter[i])) {
      finalObj.push(scaledNonProfileUsers_filter[i])
    }
  }
  function eleContainsInArray(arr, element) {
    if (arr != null && arr.length > 0) {
      for (var i = 0; i < arr.length; i++) {
        if (arr[i] == element)
          return true;
      }
    }
    return false;
  }

  console.log(finalObj)

任何幫助將不勝感激。

Answer 1

 const activeUsers = [ { org_id: 1, user_id: 9, firstName: 'Joj', lastName: 'Blonde', email: 'bop@test.ca', }, { org_id: 1, user_id: 1, firstName: 'Tyler', lastName: 'Whitfield', email: 'tyler@atg.net', }, ] const inactiveUsers = [ { org_id: 1, user_id: 3, firstName: 'James', lastName: 'Bond', email: 'test@test.ca', }, { org_id: 1, user_id: 2, firstName: 'Chen', lastName: 'rain', email: 'posihdun@gmail.com', }, ] const nonProfileUsers = [ { org_id: 2, user_id: 2, firstName: 'Chen', lastName: 'rain', email: 'posihdun@gmail.com', }, { org_id: 3, user_id: 6, firstName: 'weak', lastName: 'jdf', email: 'not@not.ca', }, { org_id: 3, user_id: 2, firstName: 'Chen', lastName: 'rain', email: 'posihdun@gmail.com', }, { org_id: 4, user_id: 2, firstName: 'Chen', lastName: 'rain', email: 'posihdun@gmail.com', }, { org_id: 3, user_id: 3, firstName: 'James', lastName: 'Bond', email: 'test@test.ca', }, { org_id: 2, user_id: 5, firstName: 'test', lastName: 'test', email: 'tester@tester.ca', }, { org_id: 2, user_id: 3, firstName: 'James', lastName: 'Bond', email: 'test@test.ca', }, ] const filteredNonProfileUsers = nonProfileUsers.reduce((prev, current) => { if ( prev.find( user => user.user_id === current.user_id || user.email === current.email ) ) return prev return [...prev, current] }, []) const activeUsersAndInactiveUsers = [...activeUsers, ...inactiveUsers] const result = filteredNonProfileUsers.reduce((prev, current) => { if ( activeUsersAndInactiveUsers.find( user => user.user_id === current.user_id || user.email === current.email ) ) return prev return [...prev, current] }, []) console.log(result)

Answer 2

使用reduce()在數組內循環，使用include()過濾元素匹配或不匹配：

 var activeUsers = [ { "org_id": 1, "user_id": 9, "firstName": "Joj", "lastName": "Blonde", "email": "bop@test.ca", }, {"org_id": 1, "user_id": 1, "firstName": "Tyler", "lastName": "Whitfield", "email": "tyler@atg.net", }, ] var inactiveUsers = [ { "org_id": 1, "user_id": 3, "firstName": "James", "lastName": "Bond", "email": "test@test.ca", }, {"org_id": 1, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", } ] //user that are in different profiles var nonProfileUsers = [ { "org_id": 2, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", }, { "org_id": 3, "user_id": 6, "firstName": "weak", "lastName": "jdf", "email": "not@not.ca", }, { "org_id": 3, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", }, { "org_id": 4, "user_id": 2, "firstName": "Chen", "lastName": "rain", "email": "posihdun@gmail.com", }, { "org_id": 3, "user_id": 3, "firstName": "James", "lastName": "Bond", "email": "test@test.ca", }, { "org_id": 2, "user_id": 5, "firstName": "test", "lastName": "test", "email": "tester@tester.ca", }, { "org_id": 2, "user_id": 3, "firstName": "James", "lastName": "Bond", "email": "test@test.ca", }, ] const scaledNonProfileUsers = nonProfileUsers.reduce((prev, curr) => (prev.map(el => el.user_id).includes(curr.user_id) || prev.map(el => el.email).includes(curr.email)) ? [...prev] : [...prev, curr], []) const combinedUsers = [...inactiveUsers, ...activeUsers] const finalObj = scaledNonProfileUsers.reduce((prev, curr) => (combinedUsers.map(el => el.email).includes(curr.email)) ? [...prev] : [...prev, curr], []) console.log(finalObj)